On Thursday, 29 March 2018 at 20:26:59 UTC, kdevel wrote:
What is the lifetime of the first loop's variable i?
It lives as long as the delegate.
What about this example:
``` bug2.d
import std.stdio;
void main ()
{
int delegate () [] dg;
foreach (i; 0..2) {
int *j;
if (i
On Thursday, 29 March 2018 at 20:05:35 UTC, ag0aep6g wrote:
On Thursday, 29 March 2018 at 19:02:51 UTC, kdevel wrote:
On Thursday, 29 March 2018 at 15:16:07 UTC, Ivan Kazmenko
wrote:
[...]
int delegate () [] guns;
foreach (i; 0..2) guns ~= () => i;
foreach (i; 0..2)
On Thursday, 29 March 2018 at 19:02:51 UTC, kdevel wrote:
On Thursday, 29 March 2018 at 15:16:07 UTC, Ivan Kazmenko wrote:
[...]
int delegate () [] guns;
foreach (i; 0..2) guns ~= () => i;
foreach (i; 0..2) writeln (guns[i] ()); // 1 and 1, why?
Isn't this undefined
On Thursday, 29 March 2018 at 15:16:07 UTC, Ivan Kazmenko wrote:
import std.stdio;
void main () {
int delegate () [] funs;
funs ~= () => 0;
funs ~= () => 1;
foreach (i; 0..2) writeln (funs[i] ()); // 0 and 1 as expected
int delegate () [] guns;
On Thursday, 29 March 2018 at 15:38:14 UTC, ag0aep6g wrote:
<...> With immutable, this is certainly a problem.
https://issues.dlang.org/show_bug.cgi?id=2043
Wow, such history for the bug!
Two possible workarounds:
int delegate () [] iuns;
foreach (i; 0..2) iuns ~= (j) { return () =>
On Thursday, 29 March 2018 at 15:16:07 UTC, Ivan Kazmenko wrote:
So, why do delegates of guns[] and huns[] all return 1, and how
to correctly reproduce the behavior of funs[] while populating
it in a loop?
A delegate is a function with a pointer to the stack frame where
it was created. It
On 03/29/2018 05:16 PM, Ivan Kazmenko wrote:
int delegate () [] guns;
foreach (i; 0..2) guns ~= () => i;
foreach (i; 0..2) writeln (guns[i] ()); // 1 and 1, why?
Because there's only variable `i`. All delegates refer to that same one.
With `i` being mutable, this could maybe
Here's a simplified example of what I want to achieve.
I first create funs, an array of two delegates.
I want funs[0] to always return 0 and funs[1] to always return 1.
By assigning the constants directly (see the code below), I
achieve exactly that.
Now, I want to use a loop to assign the
