On Sunday, 17 May 2015 at 18:49:40 UTC, dan wrote:
Is it possible to define a class F so that
auto f=new F();
writeln("The value of f at 7 is ",f(7));
compiles and works as expected?
So the idea would be to be able to use notation like
f(7)
instead of
f.eval(7)
or something along
Is it possible to define a class F so that
auto f=new F();
writeln("The value of f at 7 is ",f(7));
compiles and works as expected?
So the idea would be to be able to use notation like
f(7)
instead of
f.eval(7)
or something along those lines.
My guess is no, it is impossible to d
On 05/17/2015 11:49 AM, dan wrote:
i can't find it on the internet
There is the following short section as well:
http://ddili.org/ders/d.en/operator_overloading.html#ix_operator_overloading.opCall
Ali
On Sunday, 17 May 2015 at 18:58:32 UTC, Namespace wrote:
http://dlang.org/operatoroverloading.html#function-call
Like this:
module main;
import std.stdio;
class F
{
int opCall(int value)
{
return value * 2;
}
}
void main(string[] args)
{
auto
Awesome!!
Thanks Gary and namespace (and obviously i gotta improve my
google-fu).
dan
On Sunday, 17 May 2015 at 19:40:10 UTC, Gary Willoughby wrote:
On Sunday, 17 May 2015 at 18:58:32 UTC, Namespace wrote:
http://dlang.org/operatoroverloading.html#function-call
Like this:
module main;
i
