On Sunday, January 15, 2012 11:23:04 H. S. Teoh wrote:
> On Sat, Jan 14, 2012 at 07:53:10PM -0800, Jonathan M Davis wrote:
> [...]
>
> > Actually, if the word has to match exactly, then startsWith isn't
> > going to cut it. What you need to do is outright strip the punctuation
> > from both ends.
On Sat, Jan 14, 2012 at 07:53:10PM -0800, Jonathan M Davis wrote:
[...]
> Actually, if the word has to match exactly, then startsWith isn't
> going to cut it. What you need to do is outright strip the punctuation
> from both ends. You'd need something more like
>
> word = find!(not!(std.uni.isPun
On Saturday, January 14, 2012 19:45:55 Jonathan M Davis wrote:
> If you have to worry about punctuation, then == isn't going to work. You'll
> need to use some other combination of functions to strip the punctuation
> from one or both ends of the word. One possible solution would be something
> lik
On Saturday, January 14, 2012 19:13:02 H. S. Teoh wrote:
> On Fri, Jan 13, 2012 at 09:30:35PM -0800, Jonathan M Davis wrote:
> > On Friday, January 13, 2012 18:47:19 H. S. Teoh wrote:
> [...]
>
> > > But what I really want to accomplish is to parse a string containing
> > > multiple words; at each
On Fri, Jan 13, 2012 at 09:30:35PM -0800, Jonathan M Davis wrote:
> On Friday, January 13, 2012 18:47:19 H. S. Teoh wrote:
[...]
> > But what I really want to accomplish is to parse a string containing
> > multiple words; at each point I have a list of permitted words that
> > need to be matched ag
On Friday, January 13, 2012 18:47:19 H. S. Teoh wrote:
> On Fri, Jan 13, 2012 at 09:36:07PM -0500, Jonathan M Davis wrote:
> > On Friday, January 13, 2012 16:48:00 H. S. Teoh wrote:
> > > Hi all,
> > >
> > > I'm reading the docs for startsWith(A,B...) with multiple ranges in
> > > B,
> > > and it
On Fri, Jan 13, 2012 at 09:36:07PM -0500, Jonathan M Davis wrote:
> On Friday, January 13, 2012 16:48:00 H. S. Teoh wrote:
> > Hi all,
> >
> > I'm reading the docs for startsWith(A,B...) with multiple ranges in B,
> > and it seems that it will always match the *shortest* range whenever
> > more th
On Friday, January 13, 2012 16:48:00 H. S. Teoh wrote:
> Hi all,
>
> I'm reading the docs for startsWith(A,B...) with multiple ranges in B,
> and it seems that it will always match the *shortest* range whenever
> more than one range in B matches. Is there a way to make it always match
> the *longe
Hi all,
I'm reading the docs for startsWith(A,B...) with multiple ranges in B,
and it seems that it will always match the *shortest* range whenever
more than one range in B matches. Is there a way to make it always match
the *longest* range instead? Or do I have to write my own function for
that?
