On Monday, 1 August 2022 at 23:35:13 UTC, pascal111 wrote:
This is the definition of "filter" function, and I think it
called itself within its definition. I'm guessing how it works?
It's a template that defines the function called "Eponymous
Templates":
https://dlang.org/spec/template.html#i
On Monday, 1 August 2022 at 00:23:21 UTC, Hipreme wrote:
On Sunday, 31 July 2022 at 19:25:51 UTC, Hipreme wrote:
[...]
Seems that is how it should be checked:
```d
enum hasOverload(T, string member, FuncType)()
{
bool ret;
static foreach(overload; __traits(getVirt
This is the definition of "filter" function, and I think it
called itself within its definition. I'm guessing how it works?
'''D
template filter(alias predicate)
if (is(typeof(unaryFun!predicate)))
{
/**
Params:
range = An $(REF_ALTTEXT input range, isInputRange,
std,range,primi
On 8/1/22 15:47, Steven Schveighoffer wrote:
You beat me to it. I used .object and .str:
import std;
void main()
{
JSONValue data = parseJSON(`{ "name": "Hype Editor", "hobby":
"Programming" }`);
writefln("%s", data);
// This already sees the data as an AA but the type is
JSONVa
On 8/1/22 2:00 PM, hype_editor wrote:
I need to convert variable of type `JSONValue` to variable of type
`string[string]` (AssociativeArray).
```d
import std.json : JSONValue;
import std.stdio : writefln;
void main()
{
JSONValue data = parseJSON(`{ "name": "Hype Editor", "hobby":
"Progra
On Monday, 1 August 2022 at 17:02:10 UTC, Salih Dincer wrote:
When printing the steps `import std.stdio : writeln;` use it.
Thus, it does not conflict with `std.file`.
SDB@79
Will do and thank you for this.
On Monday, 1 August 2022 at 16:11:52 UTC, frame wrote:
... because loading all in memory while not necessary is wasted
memory if you have large files to process.
Noted with thanks. Actually, some JSON input files are pretty
large (>1Mb).
I would just process each file and write it to the fi
On Monday, 1 August 2022 at 21:35:19 UTC, Ivan Kazmenko wrote:
On Monday, 1 August 2022 at 20:36:12 UTC, pascal111 wrote:
My complaint is about that a function is not a same as an
expression that functions return values, but expressions being
evaluated to provide values.
An analogy.
With a t
On Monday, 1 August 2022 at 20:36:12 UTC, pascal111 wrote:
My complaint is about that a function is not a same as an
expression that functions return values, but expressions being
evaluated to provide values.
An analogy.
With a ternary expression, we write:
`x = (cond ? a : b);`
The tradition
On Monday, 1 August 2022 at 19:32:41 UTC, Paul Backus wrote:
On Monday, 1 August 2022 at 14:52:03 UTC, pascal111 wrote:
[...]
From [the relevant section of the language spec:][1]
[...]
In other words, a function literal is an expression that
evaluates to either a delegate or a function po
On Monday, 1 August 2022 at 14:52:03 UTC, pascal111 wrote:
If `foo => bar` == `(foo) { return bar; }`, then `foo => bar`
is a function. "=>" is not an operator, it's a special symbol
for lambda "function".
If A == B, so A's types is the same of B's type. How can it be
withstanding `foo => ba
On Monday, 1 August 2022 at 07:35:34 UTC, Christian Köstlin wrote:
[...]
```
An arguably shorter solution (that drops some of your logging)
could be:
```d
import std;
void main() {
dirEntries(".", "*.json", SpanMode.shallow)
.filter!(f => !f.name.canFind("output"))
.map!(r
On Monday, 1 August 2022 at 17:01:33 UTC, frame wrote:
On Monday, 1 August 2022 at 14:15:31 UTC, pascal111 wrote:
[...]
In C ";" is a termination character, in D is more like to
separate statements.
The lexer wouldn't need ";" for most cases like JavaScript and
the expression syntax withou
I need to convert variable of type `JSONValue` to variable of
type `string[string]` (AssociativeArray).
```d
import std.json : JSONValue;
import std.stdio : writefln;
void main()
{
JSONValue data = parseJSON(`{ "name": "Hype Editor", "hobby":
"Programming" }`);
writefln("%s", data);
On Monday, 1 August 2022 at 13:31:15 UTC, test123 wrote:
please help me give any suggestion how to handle this problem.
errno = ?
On Monday, 1 August 2022 at 17:07:43 UTC, wjoe wrote:
On Monday, 1 August 2022 at 13:09:01 UTC, Kagamin wrote:
Bar.toString is typed `@system`.
Even if I'd declare everything @safe: at module scope?
I wrote that on my phone and it got a bit messy...
``` D
module x;
@safe:
struct Foo()
{
On Monday, 1 August 2022 at 13:09:01 UTC, Kagamin wrote:
Bar.toString is typed `@system`.
Even if I'd declare everything @safe: at module scope?
On Monday, 1 August 2022 at 08:48:28 UTC, ikelaiah wrote:
On Monday, 1 August 2022 at 07:35:34 UTC, Christian Köstlin
wrote:
An arguably shorter solution (that drops some of your logging)
could be:
```d
import std;
void main() {
dirEntries(".", "*.json", SpanMode.shallow)
.filte
On Monday, 1 August 2022 at 14:15:31 UTC, pascal111 wrote:
We all know the strange syntax of lambda function within filter
algorithm like "auto r = chain(a, b).filter!(a => a > 0);". My
note is, don't we break D rules by leaving ";" after lambda
function syntax?!
Many of D rules are taken fro
On Monday, 1 August 2022 at 09:01:35 UTC, ikelaiah wrote:
Based in your suggestion, the snippet is now more brief.
While your string attempt wasn't that bad, because loading all in
memory while not necessary is wasted memory if you have large
files to process. I would just process each file
On Monday, 1 August 2022 at 16:00:50 UTC, ag0aep6g wrote:
On Monday, 1 August 2022 at 15:52:34 UTC, pascal111 wrote:
But how can we accept that both are functions and expressions
at the same time and we know that expressions can be used to
build functions themselves?!! I think they are not the
On Monday, 1 August 2022 at 15:52:34 UTC, pascal111 wrote:
But how can we accept that both are functions and expressions
at the same time and we know that expressions can be used to
build functions themselves?!! I think they are not the same.
This is getting ridiculous. I'm out.
On Monday, 1 August 2022 at 15:39:06 UTC, ag0aep6g wrote:
On Monday, 1 August 2022 at 15:31:51 UTC, pascal111 wrote:
Surely, because it seems that you are real man, your word must
be taken. Isn't `(foo) { return bar; }` an anonymous function
or am I a wrong?!! It IS a function, not an expressio
On Monday, 1 August 2022 at 15:31:51 UTC, pascal111 wrote:
Surely, because it seems that you are real man, your word must
be taken. Isn't `(foo) { return bar; }` an anonymous function
or am I a wrong?!! It IS a function, not an expression.
It's both an anonymous function and an expression. I d
On Monday, 1 August 2022 at 15:08:04 UTC, ag0aep6g wrote:
On Monday, 1 August 2022 at 14:52:03 UTC, pascal111 wrote:
If `foo => bar` == `(foo) { return bar; }`, then `foo => bar`
is a function. "=>" is not an operator, it's a special symbol
for lambda "function".
If A == B, so A's types is t
On Monday, 1 August 2022 at 14:52:03 UTC, pascal111 wrote:
If `foo => bar` == `(foo) { return bar; }`, then `foo => bar`
is a function. "=>" is not an operator, it's a special symbol
for lambda "function".
If A == B, so A's types is the same of B's type. How can it be
withstanding `foo => ba
On Monday, 1 August 2022 at 14:46:33 UTC, ag0aep6g wrote:
On Monday, 1 August 2022 at 14:39:17 UTC, pascal111 wrote:
On Monday, 1 August 2022 at 14:34:45 UTC, ag0aep6g wrote:
[...]
`a => a > 0` is not a statement. It's an expression.
But it is still a "function", and functions make statement
On Monday, 1 August 2022 at 14:39:17 UTC, pascal111 wrote:
On Monday, 1 August 2022 at 14:34:45 UTC, ag0aep6g wrote:
[...]
`a => a > 0` is not a statement. It's an expression.
But it is still a "function", and functions make statements!!
It's not a normal expression.
It's a normal expressi
On Monday, 1 August 2022 at 14:34:45 UTC, ag0aep6g wrote:
On Monday, 1 August 2022 at 14:15:31 UTC, pascal111 wrote:
Many of D rules are taken from C, we know that, so a general
basic rule is to put ";" after each statement, so the previous
statement of filter should be "auto r = chain(a, b).fi
On Monday, 1 August 2022 at 14:15:31 UTC, pascal111 wrote:
Many of D rules are taken from C, we know that, so a general
basic rule is to put ";" after each statement, so the previous
statement of filter should be "auto r = chain(a, b).filter!(a
=> a > 0;);"? Why D leaves ";" in this case?
`a
We all know the strange syntax of lambda function within filter
algorithm like "auto r = chain(a, b).filter!(a => a > 0);". My
note is, don't we break D rules by leaving ";" after lambda
function syntax?!
Many of D rules are taken from C, we know that, so a general
basic rule is to put ";" af
I have an app, when it start localtime_r return correct value.
after some time, localtime_r return Thu Jan 1 0:00:00 1970 for
same input value.
please help me give any suggestion how to handle this problem.
On Monday, 1 August 2022 at 12:58:27 UTC, Paul Backus wrote:
On Monday, 1 August 2022 at 11:35:25 UTC, pascal111 wrote:
I noticed that filter is using the concept of templates but
this time it's with a lambda function, not with a data type,
how can we explain this? isn't supposed to use a data
Bar.toString is typed `@system`.
On Monday, 1 August 2022 at 11:35:25 UTC, pascal111 wrote:
I noticed that filter is using the concept of templates but
this time it's with a lambda function, not with a data type,
how can we explain this? isn't supposed to use a data type
after the exclamation mark: "auto r = chain(a, b).filter
On Wednesday, 27 July 2022 at 11:09:19 UTC, Ali Çehreli wrote:
On 7/27/22 04:00, pascal111 wrote:
I noticed more than once that the exclamation "!" is used
within functions typing, and it seems like an operator with
new use, for example "to!int()", ".tee!(l => sum +=
l.length)", "enforce!Missi
struct Foo()
{
import std.format: FormatSpec;
const void toString(
scope void delegate(const(char)[]) @safe sink,
FormatSpec!char fmt)
{}
}
struct Bar
{
import std.format: FormatSpec;
const void toString(
scope void delegate(const(char)[]) @safe sink,
FormatSpec!char fmt
On Monday, 1 August 2022 at 05:52:36 UTC, frame wrote:
If the JSON files are already parsed, why you stringify and
reparse it?
Because of ...
1. mental block and
2. I didn't know `jsonResult.array = [];`
Many thanks for pointing this out. I tried the following, and
didn't work, and henc
On Monday, 1 August 2022 at 07:35:34 UTC, Christian Köstlin wrote:
An arguably shorter solution (that drops some of your logging)
could be:
```d
import std;
void main() {
dirEntries(".", "*.json", SpanMode.shallow)
.filter!(f => !f.name.canFind("output"))
.map!(readText)
On 2022-08-01 06:24, ikelaiah wrote:
Hi,
I've written a cli tool to merge JSON files (containing JSON array) in
the current folder as a single JSON file.
My algorithm:
1. Create a string to store the output JSON array as a string,
2. read each file
3. read each object in JSON array from inpu
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