On 4/4/14, Meta jared...@gmail.com wrote:
alias TemplateArgs(T: Foo!U, U) = U;
It's also in std.traits, TemplateArgsOf, which is more complete.
On Friday, 4 April 2014 at 07:23:51 UTC, Andrej Mitrovic wrote:
On 4/4/14, Meta jared...@gmail.com wrote:
alias TemplateArgs(T: Foo!U, U) = U;
It's also in std.traits, TemplateArgsOf, which is more complete.
I thought I remembered that being in std.traits, but I couldn't
find it after
If you have a templated type, is there a way to get the compile-time
parameters it was instantiated with?
Ie:
--
struct Foo(T) {}
alias MyFoo = Foo!int;
--
Is there a way to inspect MyFoo to get its T type (in this case, 'int')?
*Without* actually
On Friday, 4 April 2014 at 04:44:56 UTC, Nick Sabalausky wrote:
If you have a templated type, is there a way to get the
compile-time parameters it was instantiated with?
Ie:
--
struct Foo(T) {}
alias MyFoo = Foo!int;
--
Is there a way to inspect MyFoo
On 4/4/2014 1:02 AM, Meta wrote:
alias TemplateArgs(T: Foo!U, U) = U;
void main()
{
assert(is(TemplateArgs!MyFoo == int));
}
Ahh thanks.
