Re: Creating an array of immutable objects
On 2017-02-15 01:08, David Zhang wrote:
Thanks for your answers. Out of curiosity though, how could something
like this be done with classes instead?
You mean if FileDesc was a class? It's basically the same. You would need:
Mutable array:
1. Add a constructor which sets all immutable instance variables
For immutable array:
0. Same as above
1. The constructor needs to be declared as "immutable"
2. The instances need to be created with "immutable new"
In the example below, there are two constructors, one for creating
mutable instances and one for immutable instances. This is only needed
since I'm creating both a mutable and an immutable array with the same
type. You only need one kind of constructor if you only need a mutable
or an immutable array.
module main;
immutable string[] paths = [ "hello", "world" ];
class FileDesc {
immutable string path;
immutable uint index;
this(string path, uint index) immutable
{
this.path = path;
this.index = index;
}
this(string path, uint index)
{
this.path = path;
this.index = index;
}
}
// immutable array created at compile time
immutable _fileDesc = paths
.enumerate!uint
.map!(t => new immutable FileDesc(t.value, t.index))
.array;
// mutable array created at application start using allocators
FileDesc[] _fileDesc2;
auto makeFileDescs(const string[] paths)
{
return paths.enumerate!uint.map!(t => new FileDesc(t.value, t.index));
}
static this()
{
import std.experimental.allocator;
_fileDesc2 = theAllocator.makeArray!(FileDesc)(makeFileDescs(paths));
}
--
/Jacob Carlborg
Re: Creating an array of immutable objects
Thanks for your answers. Out of curiosity though, how could something like this be done with classes instead?
Re: Creating an array of immutable objects
On 2017-02-14 01:59, David Zhang wrote:
Hi,
I have a struct with two immutable members, and I want to make an array
of them. How do I to this? I'm using allocators for this.
string[] paths;
struct FileDesc {
immutable string path;
immutable uint index;
}
_fileDesc = /*something*/;
You can't use alloc.makeArray because it requires a range with which to
initialize the array, and while I can produce an array of paths, I don't
know how to merge both a range of paths and indices. Lockstep doesn't work.
I also tried using emplace and an allocated byte array, but it gave me
random values and was (I think) unnecessarily complicated. What am I
missing?
Here are two examples, one creating an immutable array at compile time.
The other one creating a mutable array at application startup using
allocators:
import std.algorithm;
import std.range;
immutable string[] paths = [ "hello", "world" ];
struct FileDesc {
immutable string path;
immutable uint index;
}
// immutable array created at compile time
immutable _fileDesc = makeFileDescs(paths).array;
// mutable array created at application start using allocators
FileDesc[] _fileDesc2;
auto makeFileDescs(const string[] paths)
{
return paths.enumerate!uint.map!(t => FileDesc(t.value, t.index));
}
static this()
{
import std.experimental.allocator;
_fileDesc2 = theAllocator.makeArray!FileDesc(makeFileDescs(paths));
}
--
/Jacob Carlborg
Re: Creating an array of immutable objects
On 02/13/2017 04:59 PM, David Zhang wrote:
I have a struct with two immutable members, and I want to make an array
of them. How do I to this? I'm using allocators for this.
I realize that I misunderstood you; see below for a mutable array.
The following code produces an immutable array through the use of the
misplaced std.exception.assumeUnique. (Why is it in std.exception? :) )
import std.stdio;
import std.algorithm;
import std.range;
string[] paths = [ "hello", "world" ];
struct FileDesc {
immutable string path;
immutable uint index;
}
immutable(FileDesc[]) _fileDesc;
FileDesc[] makeFileDescs(string[] paths) pure {
return paths.enumerate!uint.map!(t => FileDesc(t[1], t[0])).array;
}
static this() {
import std.exception : assumeUnique;
auto fd = makeFileDescs(paths);
_fileDesc = assumeUnique(fd);
}
void main() {
_fileDesc.each!writeln;
}
A mutable array is simpler:
import std.stdio;
import std.algorithm;
import std.range;
string[] paths = [ "hello", "world" ];
struct FileDesc {
immutable string path;
immutable uint index;
}
FileDesc[] _fileDesc;
FileDesc[] makeFileDescs(string[] paths) pure {
return paths.enumerate!uint.map!(t => FileDesc(t[1], t[0])).array;
}
static this() {
_fileDesc = makeFileDescs(paths);
}
void main() {
_fileDesc.each!writeln;
}
Ali
Creating an array of immutable objects
Hi,
I have a struct with two immutable members, and I want to make an
array of them. How do I to this? I'm using allocators for this.
string[] paths;
struct FileDesc {
immutable string path;
immutable uint index;
}
_fileDesc = /*something*/;
You can't use alloc.makeArray because it requires a range with
which to initialize the array, and while I can produce an array
of paths, I don't know how to merge both a range of paths and
indices. Lockstep doesn't work.
I also tried using emplace and an allocated byte array, but it
gave me random values and was (I think) unnecessarily
complicated. What am I missing?
