Re: How use Predicate (alias pred = "a*b")?
On Thursday, 13 May 2021 at 21:38:25 UTC, Adam D. Ruppe wrote:
On Thursday, 13 May 2021 at 21:30:43 UTC, Marcone wrote:
template foo(alias pred = "a*b"){
void foo(int x, int y){
writeln(x.unaryFun!pred);
First, you really shouldn't use these at all. instead of a
string, just pass an actual function to the thing as the
predicate.
but if you must use it, unaryFun has one argument, so just a.
if you want a and b, two arguments, that's binaryFun.
Thank you. binaryFun solved the problem.
Re: How use Predicate (alias pred = "a*b")?
On Thursday, 13 May 2021 at 21:38:25 UTC, Adam D. Ruppe wrote:
On Thursday, 13 May 2021 at 21:30:43 UTC, Marcone wrote:
template foo(alias pred = "a*b"){
void foo(int x, int y){
writeln(x.unaryFun!pred);
First, you really shouldn't use these at all. instead of a
string, just pass an actual function to the thing as the
predicate.
but if you must use it, unaryFun has one argument, so just a.
if you want a and b, two arguments, that's binaryFun.
This is just a simple example of how it works. I won't use it.
However, I believe it will be very useful for meta programming.
Re: How use Predicate (alias pred = "a*b")?
On Thursday, 13 May 2021 at 21:30:43 UTC, Marcone wrote:
template foo(alias pred = "a*b"){
void foo(int x, int y){
writeln(x.unaryFun!pred);
First, you really shouldn't use these at all. instead of a
string, just pass an actual function to the thing as the
predicate.
but if you must use it, unaryFun has one argument, so just a. if
you want a and b, two arguments, that's binaryFun.
How use Predicate (alias pred = "a*b")?
import std;
template foo(alias pred = "a*b"){
void foo(int x, int y){
writeln(x.unaryFun!pred);
}
}
void main(){
foo(5, 4);
}
"a" works, but "b" not work.
I get this error: Error: undefined identifier `b`
