On Tuesday, 30 August 2016 at 21:35:29 UTC, ag0aep6g wrote:
On 08/30/2016 11:28 PM, wobbles wrote:
I'll have to try find a workaround for now :/
This seems to work and isn't too ugly:
class Node(T, alias func) {/*...*/}
alias Node(T) = Node!(T, (T t) => t*t);
Excellent - thanks
On 08/30/2016 11:28 PM, wobbles wrote:
I'll have to try find a workaround for now :/
This also seems to work, but has a slightly different meaning:
class Node(T, alias func = t => t*t) {/* ... */}
The default func is a template here. Equivalent to this:
auto square(T)(T t) {
On 08/30/2016 11:28 PM, wobbles wrote:
I'll have to try find a workaround for now :/
This seems to work and isn't too ugly:
class Node(T, alias func) {/*...*/}
alias Node(T) = Node!(T, (T t) => t*t);
On Tuesday, 30 August 2016 at 20:55:20 UTC, ag0aep6g wrote:
On 08/30/2016 10:41 PM, wobbles wrote:
class Node(T, alias func = (T t => t*t))(){
//whatever
}
//instantiate
Node!(int) intNode;
Node!(float) floatNode; // fails as lambda func expects an
int.
Am I doing something wrong or is
On 08/30/2016 10:41 PM, wobbles wrote:
class Node(T, alias func = (T t => t*t))(){
//whatever
}
//instantiate
Node!(int) intNode;
Node!(float) floatNode; // fails as lambda func expects an int.
Am I doing something wrong or is this a bug?
Proper test case:
class Node(T, alias func =
Hi,
Code here:
https://gist.github.com/grogancolin/066a8a8c105fa473dfee961e2481a30e
Basically, it seems when a template has an alias parameter like
class Node(T, alias func = (T t => t*t))(){
//whatever
}
//instantiate
Node!(int) intNode;
Node!(float) floatNode; // fails as lambda func
