Re: Templating Function Names

2016-12-08 Thread Ali Çehreli via Digitalmars-d-learn

On 12/08/2016 10:21 AM, Bryce Kellogg wrote:

> It should look like Foo always had a property named after their 
custom Component.


opDispatch?

  https://dlang.org/spec/operatoroverloading.html#dispatch

Ali



Templating Function Names

2016-12-08 Thread Bryce Kellogg via Digitalmars-d-learn
Say I've got a bunch of classes that inherit from a common 
interface (in this case Component) and a class Foo that can 
handle any subclass of Component. Like so:


interface Component { ... }
class A : Component { ... }
class B : Component { ... }
class C : Component { ... }

class Foo {
alias a = this.of!A;
alias b = this.of!B;
alias c = this.of!C;
void of(T : Component)(T t) { ... }
}

It's pretty trivial to access a specific component using regular 
templates:


f.of!A = new A();
f.of!B = new B();
f.of!C = new C();

And I can alias the instantiations of these templates as seen 
above for a cleaner interface:


f.a = new A();
f.b = new B();
f.c = new C();

However, suppose I have the following situation:

void main() {
Foo f = new Foo();
class D : Component { ... }

f.of!D = new D(); // works fine
f.d = new D();// fails to compile (for obvious reason)
}

Is there a way I can get a function of Foo named after D (like 
f.d() or f.D()) without knowing before hand every single subclass 
of Component and adding aliases manually?


For example, is there a way to template the name of the function 
or an alias like:


void T(T : Component)(T t) { ... }
or
alias T = this.of!T;

Both of these just gave me functions named T.

The important thing is that it's transparent to the person 
creating a new subclass of Component. It should look like Foo 
always had a property named after their custom Component.


Is this possible?

Thanks!
Bryce