On Friday, 9 July 2021 at 11:56:40 UTC, Ali Çehreli wrote:
In addition to what others said, you can take advantage of
ranges to separate concerns of filtering and iteration. Here
are two ways:
[...]
Of course another help from the legend himself ;) As always
thanks a lot and have an
On 7/9/21 12:21 AM, rempas wrote:
>while (prompt[i] != '{' && i < len) {
In addition to what others said, you can take advantage of ranges to
separate concerns of filtering and iteration. Here are two ways:
import core.stdc.stdio;
import std.algorithm;
// Same as your original
void
On Friday, 9 July 2021 at 07:54:44 UTC, zjh wrote:
On Friday, 9 July 2021 at 07:21:06 UTC, rempas wrote:
I have the following code:
`prompt[i]!='{'`,here,i=len.so `array overflow`
Thanks a lot. It seems I have a lot to learn. Have an amazing day!
On Friday, 9 July 2021 at 07:38:50 UTC, Mike Parker wrote:
On Friday, 9 July 2021 at 07:21:06 UTC, rempas wrote:
When I execute it, I'm getting a range violation error. If I
try to set "len" to be the length of the "prompt" minus 1,
then it will work and it will print the "prompt" until the
On Friday, 9 July 2021 at 07:21:06 UTC, rempas wrote:
I have the following code:
`prompt[i]!='{'`,here,i=len.so `array overflow`
On Friday, 9 July 2021 at 07:21:06 UTC, rempas wrote:
When I execute it, I'm getting a range violation error. If I
try to set "len" to be the length of the "prompt" minus 1, then
it will work and it will print the "prompt" until the
questionmark. So I cannot find where the error is...
I have the following code:
```
import core.stdc.stdio;
void print(T)(string prompt, T args...) {
size_t len = prompt.length;
size_t i = 0;
while (prompt[i] != '{' && i < len) {
printf("%c", prompt[i]);
i++;
}
}
void main() {
print("Hello, world!\n", 10);
}
```
When I
