On Tue, 29 Dec 2009 13:44:18 -0500, teo
wrote:
On Tue, 29 Dec 2009 09:12:15 -0500, Steven Schveighoffer wrote:
Eventually, marking Prop as a @property should also work (haven't tested
it, it may work now):
@property A Prop() { return a; }
...
b.Prop += 3; // compiles
-Steve
Unfortunat
On Tue, 29 Dec 2009 09:12:15 -0500, Steven Schveighoffer wrote:
> On Tue, 29 Dec 2009 09:10:14 -0500, Steven Schveighoffer
> wrote:
>
>> On Tue, 29 Dec 2009 09:01:38 -0500, teo
>> wrote:
>>
>>> Consider following:
>>>
>>> class A
>>> {
>>> int m;
>>> void opAddAssign(int n) { m += n; }
>>>
On Tue, 29 Dec 2009 09:10:14 -0500, Steven Schveighoffer
wrote:
On Tue, 29 Dec 2009 09:01:38 -0500, teo
wrote:
Consider following:
class A
{
int m;
void opAddAssign(int n) { m += n; }
}
class B
{
A a;
this() { a = new A; }
A Prop() { return a; }
}
void main()
{
B b = new B
On Tue, 29 Dec 2009 09:01:38 -0500, teo
wrote:
Consider following:
class A
{
int m;
void opAddAssign(int n) { m += n; }
}
class B
{
A a;
this() { a = new A; }
A Prop() { return a; }
}
void main()
{
B b = new B;
b.Prop += 3;
}
I get a compilation error (dmd v2.037):
test.d(1
Consider following:
class A
{
int m;
void opAddAssign(int n) { m += n; }
}
class B
{
A a;
this() { a = new A; }
A Prop() { return a; }
}
void main()
{
B b = new B;
b.Prop += 3;
}
I get a compilation error (dmd v2.037):
test.d(17): Error: 'b.Prop' is not a scalar, it is a A()
test
