Re: Memoizing methods
On Friday, 19 December 2014 at 02:45:13 UTC, kyle wrote: If you memoize a method inside a class definition using std.functional.memoize is caching done in a per-object manner, or do all objects of this class share cached return values? Thank you. Memoize uses one hash table per symbol it is
Memoizing methods
If you memoize a method inside a class definition using std.functional.memoize is caching done in a per-object manner, or do all objects of this class share cached return values? Thank you.