On Tuesday, 25 June 2019 at 16:51:46 UTC, Nathan S. wrote:
On Sunday, 23 June 2019 at 21:24:14 UTC, Nathan S. wrote:
https://issues.dlang.org/show_bug.cgi?id=2.
The fix for this has been accepted and is set for inclusion in
DMD 2.080.
088 :)
On Sunday, 23 June 2019 at 21:24:14 UTC, Nathan S. wrote:
https://issues.dlang.org/show_bug.cgi?id=2.
The fix for this has been accepted and is set for inclusion in
DMD 2.080.
On Tuesday, 21 May 2019 at 07:59:13 UTC, Jim wrote:
On Tuesday, 21 May 2019 at 07:33:17 UTC, rumbu wrote:
On Tuesday, 21 May 2019 at 07:16:49 UTC, Jim wrote:
On Tuesday, 21 May 2019 at 07:04:27 UTC, rumbu wrote:
On Tuesday, 21 May 2019 at 05:51:30 UTC, Jim wrote:
That's because foo is of
On Tuesday, 21 May 2019 at 07:33:17 UTC, rumbu wrote:
On Tuesday, 21 May 2019 at 07:16:49 UTC, Jim wrote:
On Tuesday, 21 May 2019 at 07:04:27 UTC, rumbu wrote:
On Tuesday, 21 May 2019 at 05:51:30 UTC, Jim wrote:
That's because foo is of type Base, not implementing FeatureX.
Right, Base
On Tuesday, 21 May 2019 at 07:19:38 UTC, Marco de Wild wrote:
On Tuesday, 21 May 2019 at 05:51:30 UTC, Jim wrote:
Hi,
consider this:
interface Base
{
void setup();
}
interface FeatureX
{
void x();
}
class Foo: Base, FeatureX
{
void setup(){};
void x(){};
}
void main()
{
Base foo
On Tuesday, 21 May 2019 at 07:16:49 UTC, Jim wrote:
On Tuesday, 21 May 2019 at 07:04:27 UTC, rumbu wrote:
On Tuesday, 21 May 2019 at 05:51:30 UTC, Jim wrote:
That's because foo is of type Base, not implementing FeatureX.
Right, Base isn't implementing FeatureX, but foo is really a Foo
On Tue, May 21, 2019 at 7:55 AM Jim via Digitalmars-d-learn <
digitalmars-d-learn@puremagic.com> wrote:
> Hi,
>
> Question: How to call foo.x in @safe code ?
>
@safe:
interface Base
{
void setup();
}
interface FeatureX
{
void x();
}
interface FeatureY
{
void y();
}
class Foo: Base,
On Tuesday, 21 May 2019 at 05:51:30 UTC, Jim wrote:
Hi,
consider this:
interface Base
{
void setup();
}
interface FeatureX
{
void x();
}
class Foo: Base, FeatureX
{
void setup(){};
void x(){};
}
void main()
{
Base foo = new Foo(); // This would be the result of a
factory class
On Tuesday, 21 May 2019 at 07:04:27 UTC, rumbu wrote:
On Tuesday, 21 May 2019 at 05:51:30 UTC, Jim wrote:
That's because foo is of type Base, not implementing FeatureX.
Right, Base isn't implementing FeatureX, but foo is really a Foo
which does:
class Foo: Base, FeatureX
{
void
On Tuesday, 21 May 2019 at 05:51:30 UTC, Jim wrote:
Hi,
consider this:
interface Base
{
void setup();
}
interface FeatureX
{
void x();
}
class Foo: Base, FeatureX
{
void setup(){};
void x(){};
}
void main()
{
Base foo = new Foo(); // This would be the result of a
factory class
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