Re: Date Formating
On Wednesday, 13 December 2017 at 17:16:46 UTC, Vino wrote: On Wednesday, 13 December 2017 at 08:32:34 UTC, codephantom wrote: [...] Hi All, [...] Hi All, Thank you very much , was able to resolve the issue by changing the writefln line as below. Sorted[].sort!((a,b) => a[1] > b[1]).each!(e => writefln!"%-63s %.20s"(e[0], e[1].to!string)); From, Vino.B
Re: Date Formating
On Wednesday, 13 December 2017 at 08:32:34 UTC, codephantom wrote:
On Wednesday, 13 December 2017 at 07:35:40 UTC, Jonathan M
Davis wrote:
In general, you probably want to cast the SysTime to a
DateTime if you're going to do something like that.
yes, I would agree ;-)
Of course the intention was not really to just format it the
same way as Clock.currTime() does it, but rather to provide a
way to more easily customise the format, however one likes,
whenever one likes..
e.g.the following small change to the format string would make
it return: 20171213_1924_41
(that's more like something I'd use)
return
format("%04s%02s%02s_%02s%02s_%02s",
(d.year),
to!(int)(d.month),
(d.day),
(d.hour),
(d.minute),
(d.second)
);
Hi All,
Request your help on below program on how to format or cast
SysTime to DateTime
import std.algorithm: filter, map, sort;
import std.container.array;
import std.file: SpanMode, dirEntries, isDir ;
import std.stdio: writeln,writefln;
import std.typecons: Tuple, tuple;
import std.datetime.systime: SysTime;
void main () {
auto FFs = ["C:\\Temp\\BACKUP", "C:\\Temp\\\EXPORT"];
Array!(Tuple!(string, SysTime)) Sorted;
foreach(d; FFs[]) {
auto dFiles = Array!(Tuple!(string, SysTime))(dirEntries(d,
SpanMode.shallow).filter!(a => a.isDir).map!(a => tuple(a.name,
a.timeCreated)));
foreach(i; dFiles[]){ Sorted ~= i; }
writefln("%(%-(%-63s %s %)\n%)", Sorted[].sort!((a,b) => a[1] <
b[1]));
}
}
Output:
C:\Temp\BACKUP\DND3
2017-Sep-05 14:31:00.7037169
C:\Temp\BACKUP\DND5
2017-Sep-05 14:31:00.750517
C:\Temp\EXPORT\DND6
2017-Sep-05 14:31:00.8909172
C:\Temp\BACKUP\dir1
2017-Sep-06 16:06:42.7223837
C:\Temp\EXPORT\dir2
2017-Sep-06 16:06:43.1435864
C:\Temp\BACKUP\dir2
2017-Sep-09 22:44:11.7604069
C:\Temp\BACKUP\dir3
2017-Dec-10 06:56:07.5122231
C:\Temp\BACKUP\t1
2017-Dec-11 04:10:02.6413853
Required Output
C:\Temp\BACKUP\DND3
2017-Sep-05 14:31:00
C:\Temp\BACKUP\DND5
2017-Sep-05 14:31:00
C:\Temp\EXPORT\DND6
2017-Sep-05 14:31:00
C:\Temp\BACKUP\dir1
2017-Sep-06 16:06:42
C:\Temp\EXPORT\dir2
2017-Sep-06 16:06:43
C:\Temp\BACKUP\dir2
2017-Sep-09 22:44:11
C:\Temp\BACKUP\dir3
2017-Dec-10 06:56:07
C:\Temp\BACKUP\t1
2017-Dec-11 04:10:02
From,
Vino.B
Re: Date Formating
On Wednesday, 13 December 2017 at 07:35:40 UTC, Jonathan M Davis
wrote:
In general, you probably want to cast the SysTime to a DateTime
if you're going to do something like that.
yes, I would agree ;-)
Of course the intention was not really to just format it the same
way as Clock.currTime() does it, but rather to provide a way to
more easily customise the format, however one likes, whenever one
likes..
e.g.the following small change to the format string would make it
return: 20171213_1924_41
(that's more like something I'd use)
return
format("%04s%02s%02s_%02s%02s_%02s",
(d.year),
to!(int)(d.month),
(d.day),
(d.hour),
(d.minute),
(d.second)
);
Re: Date Formating
On Wednesday, December 13, 2017 02:34:12 codephantom via Digitalmars-d-learn
wrote:
> On Tuesday, 12 December 2017 at 15:56:59 UTC, Vino wrote:
> > Hi All,
> >
> > Request out help on date formatting, I have code which output
> >
> > the date and time as below , i we need it without the last few
> > numbers.,ie "-MMM-DD HH:MM:SI"
> >
> > Output : 2017-Sep-06 16:06:42.7223837
> > Required Output : 2017-Sep-06 16:06:42
> >
> > From,
> > Vino.B
>
> just playing with this...
>
> // --
>
> module test;
>
> void main()
> {
> import std.stdio;
>
> writeln( GetFmtDate() ); // e.g: 2017-Dec-13 13:30:23
>
> }
>
>
> string GetFmtDate()
> {
> import std.datetime;
> import std.ascii : toUpper;
> import std.conv : to;
> import std.string : format;
>
> auto d = Clock.currTime();
>
> string fmtMonth = toUpper(to!string(d.month)[0]) ~
>to!string(d.month)[1..$];
>
> return
> format("%04s-%s-%02s %02s:%02s:%02s",
> (d.year),
> fmtMonth,
> (d.day),
> (d.hour),
> (d.minute),
> (d.second)
> );
> }
>
> // --
In general, you probably want to cast the SysTime to a DateTime if you're
going to do something like that. There's a lot of duplicate work being done
if you get each of those properties individually, whereas if you cast to
DateTime, then it does the work once, and the properties for DateTime just
return the correspending member variables. Sometimes, I think that putting
year, month, etc. on SysTime was a mistake, because using thoes properties
almost always the wrong thing to do given how much work is duplicated when
using them, but at the same time, there are cases where the efficiency
doesn't really matter and the simplicity of just grabbing the properties
from SysTime is nice.
- Jonathan M Davis
Re: Date Formating
On Tuesday, 12 December 2017 at 15:56:59 UTC, Vino wrote:
Hi All,
Request out help on date formatting, I have code which output
the date and time as below , i we need it without the last few
numbers.,ie "-MMM-DD HH:MM:SI"
Output : 2017-Sep-06 16:06:42.7223837
Required Output : 2017-Sep-06 16:06:42
From,
Vino.B
just playing with this...
// --
module test;
void main()
{
import std.stdio;
writeln( GetFmtDate() ); // e.g: 2017-Dec-13 13:30:23
}
string GetFmtDate()
{
import std.datetime;
import std.ascii : toUpper;
import std.conv : to;
import std.string : format;
auto d = Clock.currTime();
string fmtMonth = toUpper(to!string(d.month)[0]) ~
to!string(d.month)[1..$];
return
format("%04s-%s-%02s %02s:%02s:%02s",
(d.year),
fmtMonth,
(d.day),
(d.hour),
(d.minute),
(d.second)
);
}
// --
Re: Date Formating
On Tuesday, December 12, 2017 15:56:59 Vino via Digitalmars-d-learn wrote: > Hi All, > >Request out help on date formatting, I have code which output > the date and time as below , i we need it without the last few > numbers.,ie "-MMM-DD HH:MM:SI" > > Output : 2017-Sep-06 16:06:42.7223837 > Required Output : 2017-Sep-06 16:06:42 If you want to strip off the fractional seconds, then just zero them out. e.g. sysTime.fracSecs = Duration.zero; The to*String functions of SysTime don't display trailing zeroes and don't display the decimal point if the fractional seconds are zero. - Jonathan M Davis
Re: Date Formating
On 12/12/17 10:56 AM, Vino wrote: Hi All, Request out help on date formatting, I have code which output the date and time as below , i we need it without the last few numbers.,ie "-MMM-DD HH:MM:SI" Output : 2017-Sep-06 16:06:42.7223837 Required Output : 2017-Sep-06 16:06:42 You need to extract the date components and print them separately. There is no mechanism to format a SysTime (and it's a hairy subject to be sure, every locale is different). -Steve
Re: Date Formating
On Tuesday, 12 December 2017 at 16:01:49 UTC, Adam D. Ruppe wrote:
On Tuesday, 12 December 2017 at 15:56:59 UTC, Vino wrote:
Request out help on date formatting, I have code which
output the date and time as below , i we need it without the
last few numbers.,ie "-MMM-DD HH:MM:SI"
Just slice it off. x[0 .. x.lastIndexOf("."];
Hi,
I tried it but no luck, as the output is a function return in
type SysTime.
From,
Vino.B
Re: Date Formating
On Tuesday, 12 December 2017 at 15:56:59 UTC, Vino wrote:
Request out help on date formatting, I have code which output
the date and time as below , i we need it without the last few
numbers.,ie "-MMM-DD HH:MM:SI"
Just slice it off. x[0 .. x.lastIndexOf("."];
