Re: convert string to ubyte[]

2017-11-11 Thread aki via Digitalmars-d-learn 

On Saturday, 11 November 2017 at 15:48:59 UTC, Mike Parker wrote:

auto s = "hello";
auto bytes = s.representation;

https://dlang.org/phobos/std_string.html#.representation


Thank you for the replay.
Now I know.

aki

Re: convert string to ubyte[]

2017-11-11 Thread bauss via Digitalmars-d-learn 

On Saturday, 11 November 2017 at 15:48:59 UTC, Mike Parker wrote:

On Saturday, 11 November 2017 at 15:38:18 UTC, aki wrote:

[...]


I don't know about the error you're seeing, but the generic way 
to get an array of the underlying data type of a string is via 
std.string.representation.


import std.string;
auto s = "hello";
auto bytes = s.representation;

https://dlang.org/phobos/std_string.html#.representation

You can also simply cast to the appropriate type if you already 
know what type of string you have.


auto bytes = cast(immutable(ubyte)[])s;

Of course, if you need a mutable array you should dup:

auto bytes = cast(ubyte[])s.dup;


That function needs to be highlighted more through documentation. 
I've always implemented my own versions to achieve the same as 
representation. I had no idea that function existed.


If just I knew.

Re: convert string to ubyte[]

2017-11-11 Thread user1234 via Digitalmars-d-learn 

On Saturday, 11 November 2017 at 15:48:59 UTC, Mike Parker wrote:

On Saturday, 11 November 2017 at 15:38:18 UTC, aki wrote:
auto bytes = cast(immutable(ubyte)[])s;

Of course, if you need a mutable array you should dup:

auto bytes = cast(ubyte[])s.dup;


Not only "should" but he "must" otherwise with string literals 
he'll get a violation access error.

Re: convert string to ubyte[]

2017-11-11 Thread Guillaume Piolat via Digitalmars-d-learn 

On Saturday, 11 November 2017 at 15:38:18 UTC, aki wrote:

Hello,

This will be trivial question but I cannot figure out
what's wrong. I want to convert string to an array of ubyte.

import std.conv;
void main() {
auto s = "hello";
ubyte[] b = to!(ubyte[])(s);
}

It compiles but cause run time error:

std.conv.ConvException@C:\APP\D\dmd2\windows\bin\..\..\src\phobos\std\conv.d(3530): Can't 
parse string: "[" is missing

I cannot understand the meaning of this message.
Replacing s with s.dup to remove immutable doesn't help.
Do I need to use cast?

Regards,
Aki


to!(ubyte[]) is a semantic transformation that tries to parse an 
array literal it seems.


You can use slice casting instead:

 import std.conv;
 void main() {
  auto s = "hello";
  ubyte[] b = cast(ubyte[])(s.dup);
 }

Re: convert string to ubyte[]

2017-11-11 Thread Mike Parker via Digitalmars-d-learn 

On Saturday, 11 November 2017 at 15:38:18 UTC, aki wrote:

Hello,

This will be trivial question but I cannot figure out
what's wrong. I want to convert string to an array of ubyte.

import std.conv;
void main() {
auto s = "hello";
ubyte[] b = to!(ubyte[])(s);
}

It compiles but cause run time error:

std.conv.ConvException@C:\APP\D\dmd2\windows\bin\..\..\src\phobos\std\conv.d(3530): Can't 
parse string: "[" is missing

I cannot understand the meaning of this message.
Replacing s with s.dup to remove immutable doesn't help.
Do I need to use cast?

Regards,
Aki


I don't know about the error you're seeing, but the generic way 
to get an array of the underlying data type of a string is via 
std.string.representation.


import std.string;
auto s = "hello";
auto bytes = s.representation;

https://dlang.org/phobos/std_string.html#.representation

You can also simply cast to the appropriate type if you already 
know what type of string you have.


auto bytes = cast(immutable(ubyte)[])s;

Of course, if you need a mutable array you should dup:

auto bytes = cast(ubyte[])s.dup;