Eric,
Right as always. Had to add some sprucing code to the html() returned. Some
values gave a NaN when parseInt-ed.
Thanks again for the help.
Liking jQuery more by the day!
Regards,
Chinmay
Erik Beeson wrote:
>
> Completely random sorting usually means there's something wrong with
> your
Completely random sorting usually means there's something wrong with
your comparing function. Try adding some debugging output in your
comparing function and make sure you're comparing the correct values
and get the expected result there.
If you actually have null values in that first if statement
I tried using the code, as suggested by Eric, but it doesn't work. In my
case, I'm trying to sort a bunch of divs based on the value of a span inside
each. However, the sorting is completely random!
I don't know what I'm doing wrong!
jQuery.noConflict();
$j = jQuery;
riggit = {
/*...*/
Eric,
I need to implement a simliar funcnality, and was looking at the trac. What
throws me offis that thetatus of the Bug was set to 'review' a few hours
ago.
Any *more* magical way to do this coming up?
Erik Beeson wrote:
>
> Even easier than that:
>
> jQuery.fn.sort = function() {
> re
Thanks Eric.
Erik Beeson said the following on 3/26/2007 9:47 AM:
> Even easier than that:
>
> jQuery.fn.sort = function() {
> return this.pushStack( jQuery.makeArray( [].sort.apply( this,
> arguments )) );
> };
>
> See here: http://dev.jquery.com/ticket/255
>
> Looks like I'm still about t
Even easier than that:
jQuery.fn.sort = function() {
return this.pushStack( jQuery.makeArray( [].sort.apply( this,
arguments )) );
};
See here: http://dev.jquery.com/ticket/255
Looks like I'm still about the only person that actually uses this.
--Erik
On 3/26/07, Luke Lutman <[EMAIL PROTE
I'd guess it's because arguments isn't really an array (it has a length
property, but none of
Array's methods).
Something like this might do the trick:
jQuery.fn.sort = function() {
for(var i = 0, args = []; i < arguments.length; i++)
args.push(i);
return this.pushStack( [].s
