On Mon, Dec 1, 2008 at 2:23 AM, David Shieh <[EMAIL PROTECTED]> wrote:
> I dont' know whether this make any sense .
> Right now , I can't test it , but if django won't initiate the
> views.py as a class , this method will make no sense.
Why not write a decorator?
---
David Zhou
[EMAIL
On Sun, 2008-11-30 at 23:42 -0800, Roy wrote:
> Hi,
>
> I have the following in one of my templates:
> Flag
>
> But I'm getting a TemplateSyntaxError:
>
> Caught an exception while rendering: Reverse for 'mysite.comments-
> flag' with arguments '(, '')'
> and keyword arguments '{}' not found
I have found a post in here :
http://davyd.livejournal.com/262859.html
this is the way this author resolves this problem.
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Hi,
I have the following in one of my templates:
Flag
But I'm getting a TemplateSyntaxError:
Caught an exception while rendering: Reverse for 'mysite.comments-
flag' with arguments '(, '')'
and keyword arguments '{}' not found
The named url "comments-flag" comes from
Oh, I got it!
{% for content_id, content in
contents.items %}
{{ content.title }}
{{ content.type }}
{{ content.relative }}
Hi, I'm a newbie in Django. I got I problem looks like below:
== contents.py ==
from testcms.contents.models import *
class Contents(UserDict):
def get_contents_list(self):
contents = Contents.objects.all()
for content in contents:
author =
No , not in that way.
Let me show you some code
#a.py
class A:
def __init__(self):
#do somthing
#views.py
class B(A):
def index(request):
#do something else
#urls.py
(r'^$', 'site.app.views.index'),
I dont' know whether this make any sense .
Right now , I can't
On Sun, 2008-11-30 at 22:46 -0800, David Shieh wrote:
> yeah , I will consider about middleware , and I am also thinking about
> write a class that contains the functions I need , and other funcions
> just inherit it , will it work ?
Since functions don't inherit from classes, your question
On Mon, Dec 1, 2008 at 2:04 PM, djan <[EMAIL PROTECTED]> wrote:
>
> Hello,
>
> I'm following along with djangobook.com, and I have a problem in
> chapter 5 that I cannot resolve. I am using OpenSuSE-11.0, Python
> 2.5.2, sqlite3-3.5.7-17.1 (and incidentally, this same error occurs
> with MySQL).
On Sun, 2008-11-30 at 21:04 -0800, djan wrote:
> Hello,
>
> I'm following along with djangobook.com, and I have a problem in
> chapter 5 that I cannot resolve. I am using OpenSuSE-11.0, Python
> 2.5.2, sqlite3-3.5.7-17.1 (and incidentally, this same error occurs
> with MySQL).
The Django book
yeah , I will consider about middleware , and I am also thinking about
write a class that contains the functions I need , and other funcions
just inherit it , will it work ?
On Dec 1, 2:41 pm, Malcolm Tredinnick <[EMAIL PROTECTED]>
wrote:
> On Sun, 2008-11-30 at 22:35 -0800, David Shieh wrote:
>
Hello,
I'm following along with djangobook.com, and I have a problem in
chapter 5 that I cannot resolve. I am using OpenSuSE-11.0, Python
2.5.2, sqlite3-3.5.7-17.1 (and incidentally, this same error occurs
with MySQL).
When I run the following:
$ python manage.py validate
I receive:
Traceback
On Sun, 2008-11-30 at 22:35 -0800, David Shieh wrote:
> Hi , Malcolm,
>
> Now , I understand what you said.But using session means user must to
> call a certain to set the session.
I was using session as an *example*. It's something that, based on
incoming request information, is run every
Hi , Malcolm,
Now , I understand what you said.But using session means user must to
call a certain to set the session.I mean , for example , I am setting
up a blog , and every page want to show the categories this blog
have . If I write these categories as a session value , I have to
write it
Hi again Malcolm,
I've now performed some of the test you suggest here, and I would like
to report my findings.
> > It seems to me that when the Python renderer sees the Decimal() call,
> > it goes and fetches my OS locale, which calls for Swedish decimal
> > commas instead of US decimal points.
I have been looking into using OpenId and I discovered that there are
to 2 django libraries that handle this: django_openId and
django_authopenid. Any opinions on the two? Not sure which one I
should go with.
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On Sun, 2008-11-30 at 21:48 -0800, David Shieh wrote:
> Thanks , Malcolm ,
>
> I think your solution can resolve my problem.But does it a bit
> complex ?
> In fact , what I really want is a view function that will be called by
> every view function.
> i.e. , if I wrote an auth system , I need
On Sun, Nov 30, 2008 at 11:48 PM, David Shieh <[EMAIL PROTECTED]> wrote:
> I think your solution can resolve my problem.But does it a bit
> complex ?
> In fact , what I really want is a view function that will be called by
> every view function.
> i.e. , if I wrote an auth system , I need to
Thanks , Malcolm ,
I think your solution can resolve my problem.But does it a bit
complex ?
In fact , what I really want is a view function that will be called by
every view function.
i.e. , if I wrote an auth system , I need to authenticate whether the
user is logged in every view functions and
On Sun, 2008-11-30 at 19:41 -0800, David Shieh wrote:
[...]
> I have searched for some information . I know that middleware can do
> this , but what I really want is just a small function for this .
A process_request() function in middleware can be as small as you like.
Middleware provides the
It is a very correct suggestion,Thank you!
On 12月1日, 上午1时49分, Daniel Roseman <[EMAIL PROTECTED]>
wrote:
> On Nov 30, 5:26 pm, l0he1g <[EMAIL PROTECTED]> wrote:
>
> > Hi,everyone,this is a beginner's first post,after a long,tired search
> > here and there without any solution.
> > I use
I have used Django for several months , and it really attacts me . I
love it.
But when I use it more , I found a problem troubles me , that is , I
can't find a way to make a function be called by every view function
automatically .
I used CakePHP , it have a function named beforeFilter() . It
On Sun, 2008-11-30 at 16:25 -0800, Andrew Arrow wrote:
> Trying to get the example from
>
> http://docs.djangoproject.com/en/dev/topics/forms/
>
> to work. I copied and pasted:
>
> from django import forms
>
> class ContactForm(forms.Form):
> subject = forms.CharField(max_length=100)
>
Trying to get the example from
http://docs.djangoproject.com/en/dev/topics/forms/
to work. I copied and pasted:
from django import forms
class ContactForm(forms.Form):
subject = forms.CharField(max_length=100)
message = forms.CharField()
sender = forms.EmailField()
cc_myself
Thank you a lot ,I think I have solved it,by add the following to
httpd.conf:
Options Indexes FollowSymLinks MultiViews
AllowOverride None
Order allow,deny
allow from all
I think the docs of django who said " would be meaningless
here." is misleading a lot.
On 12月1日,
On Sun, 2008-11-30 at 17:57 -0800, l0he1g wrote:
> I am sorry adding a initial slash doesn't solve this problem,but thank
> you for the same.
> when I get http://localhost/static directly in browser,arise a 403
> message:
> Forbidden
> You don't have permission to access /static on this server.
I am sorry adding a initial slash doesn't solve this problem,but thank
you for the same.
when I get http://localhost/static directly in browser,arise a 403
message:
Forbidden
You don't have permission to access /static on this server.
when I get http:/localhost/,I inspect the adress of images in
It is also possible to use a cronjob to initiate a script to send an e-
mail.
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On Mon, Dec 1, 2008 at 9:13 AM, Ariel Mauricio Nunez Gomez
<[EMAIL PROTECTED]> wrote:
>
>> I should be in a position to publish a git repository with my work in
>> progress in the next day or so, which will remove the need for anyone
>> to apply the patch manually. When I push the repository,
On Sun, 2008-11-30 at 07:56 -0800, Log0 wrote:
> Hi all,
>
> This string :
>
> data = ''.join( [ chr(i) for i in xrange(256) ] )
>
> In Django 0.96, this string prints well.
> In Django 1.0, this string simply disappears before going to Apache,
> and the data is never transmitted to the
On Sun, 2008-11-30 at 13:15 +0100, Alfredo Alessandrini wrote:
> Hi,
>
> I've this model:
>
> class Player(models.Model):
> user = models.ForeignKey(User, blank=True, null=True)
> country = models.ForeignKey(Country)
>
> If I try to ordering Player by "user", don' work:
>
>
On Sun, 2008-11-30 at 01:34 -0800, Ulf Kronman wrote:
> Hi Malcolm,
>
> > I forgot to mention this in my last reply, but you didn't actually
> > answer the question that Karen asked. If you open up a Python prompt on
> > your machine and do this:
> >
> > >>> import decimal
> >
On Sun, 2008-11-30 at 01:15 -0800, Daniel Roseman wrote:
[...]
> No doubt someone will correct me if I'm wrong, but I don't think there
> *is* any other way of receiving a file via POST except via a form.
You gave an answer, so it's going to look crabby to say this, but that
isn't correct. You
> I should be in a position to publish a git repository with my work in
> progress in the next day or so, which will remove the need for anyone
> to apply the patch manually. When I push the repository, I'll announce
> on the ticket and on django-developers. Watch this space.
That'd be great,
On Mon, Dec 1, 2008 at 2:04 AM, Ariel Mauricio Nunez Gomez
<[EMAIL PROTECTED]> wrote:
> Does anybody know which revision of django works with the latest patch in
> the ticket #3566
> http://code.djangoproject.com/ticket/3566
The patch on the ticket was constructed against a trunk revision just
On Nov 29, 8:26 pm, AJ <[EMAIL PROTECTED]> wrote:
> James,
>
> Thanks for the reply, I can't tell you how many times I read over that
> page in the documentation today, and didn't catch that. I think when
> this problem arose I looked over the ModelForm docs and couldn't find
> a solution.
I'm not expert at this. I've only used formsets a little, and I've
never added any dynamically. But depending upon your requirements,
you could define the formset with an adequate number of "extra=" forms
and have the javascript hide most of them by default, displaying an
additional one each
On Nov 30, 9:56 am, Log0 <[EMAIL PROTECTED]> wrote:
> Hi all,
>
> This string :
>
> data = ''.join( [ chr(i) for i in xrange(256) ] )
>
> In Django 0.96, this string prints well.
> In Django 1.0, this string simply disappears before going to Apache,
> and the data is never transmitted to the
What do you mean by "disappears"? How are you trying to output it?
There's nothing special about the string that line generates, and I
doubt anything would have changed between versions of Django that
would stop that string from doing something it used to do.
-Jeff
On Nov 30, 10:56 am, Log0
On Sat, Nov 29, 2008 at 12:24 PM, Justin Bronn <[EMAIL PROTECTED]> wrote:
>
> > I do have a few basic questions
> > - on slide 37, there's a Zipcode model, how does one populate this model?
> > Are we using fe_2007_us_zcta500.shp? If so, is there a program which
> > converts the zipcode shape
On Nov 30, 5:26 pm, l0he1g <[EMAIL PROTECTED]> wrote:
> Hi,everyone,this is a beginner's first post,after a long,tired search
> here and there without any solution.
> I use apache+mod_python on windows,The problem is the css and images
> does't be imported anyway,as I did what "How to use Django
Thanks Steve. I've got the server-side portion done, just need to now
work on the javascript. :)
On Nov 30, 9:02 am, Steve Bergman <[EMAIL PROTECTED]> wrote:
> When you add a form with javascript, you must also increment the
> hidden field in the management form which holds the form count.
>
Hi,everyone,this is a beginner's first post,after a long,tired search
here and there without any solution.
I use apache+mod_python on windows,The problem is the css and images
does't be imported anyway,as I did what "How to use Django with Apache
and mod_python" told in
Does anybody know which revision of django works with the latest patch in
the ticket #3566
http://code.djangoproject.com/ticket/3566
I tried unsuccesfully with django 1.0rc, 1.0 and 1.0.2, everytime different
rejections, and when I try to fix them by hand I always get a 'SELECT FROM
...' invalid
When you add a form with javascript, you must also increment the
hidden field in the management form which holds the form count.
Actually, you'll need to read that field before you add the form to
determine what the proper ids and names for the new input elements
should be. Validation will then
Hello,
I use the comments framework from the newest Django SVN checkout.
I have in my template:
{% load comments % }
[...]
{% render_comment_form for object %}
resulting in a Invalid block tag: 'render_comment_form'
I have found the same error in one other posting but no solution. What
is
hi,
It is mush easier then my approach. Thanks a lot!
On Fri, Nov 28, 2008 at 9:28 PM, redbaron <[EMAIL PROTECTED]> wrote:
>
>
> My current solution is.
>
> 1. Define new model Batches:
>
> class Batches(models.Model):
> batchfile = model.FileField(upload_to="noop")
>
> 2. In admin.py define
I found a solution on my own, and it's a doozy. If anyone can think of
something a bit less ugly, let me know. The reason why the global
variables are lists is to keep Python from trying to rebind the names
as local variables inside the functions on assignment (the very
behaviour that makes
Hi all,
This string :
data = ''.join( [ chr(i) for i in xrange(256) ] )
In Django 0.96, this string prints well.
In Django 1.0, this string simply disappears before going to Apache,
and the data is never transmitted to the client or even apache.
Why?
Any fix?
Thanks a lot.
---
Best
Hi all,
This string :
data = ''.join( [ chr(i) for i in xrange(256) ] )
In Django 0.96, this string prints well.
In Django 1.0, this string simply disappears before going to Apache,
and the data is never transmitted to the client or even apache.
Why?
Any fix?
Thanks a lot.
---
Best
So to clarify, I'd be modifying the new rows on the client side,
correct?
On Nov 29, 9:47 pm, "Felipe Sodré Silva" <[EMAIL PROTECTED]> wrote:
> I don't see why it wouldn't.
>
> On Sun, Nov 30, 2008 at 3:42 AM, Zeroth <[EMAIL PROTECTED]> wrote:
>
> > Thanks Felipe for your quick answer. Does that
On Nov 30, 2008, at 10:36 PM, Alex Jonsson wrote:
>
> Hey guys,
>
> I have an application where I want my users to be able to upload a
> picture. The model contains a name field and a ImageField.
>
> My question is how the easiest way would be to modify this image
> before saving it? That is,
Hey guys,
I have an application where I want my users to be able to upload a
picture. The model contains a name field and a ImageField.
My question is how the easiest way would be to modify this image
before saving it? That is, cropping it down to a certain size and
renaming it to the person's
Another problem! I'm using Django 1.0.2, Python 2.5.2, on Ubuntu 8.10.
I have a structure of keys and keyrings arranged in a tree of
arbitrary depth which I decided to implement as a bunch of models:
RootKeyRing, RootKey, SubKeyRing, SubKey (rather than as XML like
maybe I should have done)
Well, I got that fairly complicated recursive control structure
working nicely... it resembles if/else/endif, but it loops picking up
nodelists in a dictionary indexed by tag name, makes a list of the
tags it finds until the endtag, and checks the list to make sure the
syntax inside the bock was
I have an inheritance system for defining people.
So there's a class Person, and sub-class User thus:
class Person(models.Model):
''' A person! '''
firstname = models.CharField("first name", max_length = 128,
help_text = "(required)")
lastname = models.CharField("last name",
Hi,
I've this model:
class Player(models.Model):
user = models.ForeignKey(User, blank=True, null=True)
country = models.ForeignKey(Country)
If I try to ordering Player by "user", don' work:
Player.objects.order_by("user")
I want ordering Player by user.username
Alfredo
Thank you for the tip. It works well.
I have problem with processing flat pages.
When debug is switched to True the error appear in db with following content:
Traceback (most recent call last):
File "/usr/local/lib/python2.6/site-packages/django/core/handlers/base.py",
line 86, in
Ok, Solved!! It wasmy fault because I have overwritten the form widget
in the inline model.
Now I have removed the customized form.
On Nov 29, 11:16 pm, mrsource <[EMAIL PROTECTED]> wrote:
> I have models and admin configuration like these:http://dpaste.com/94671/
>
> when I edit the model
How about use this app:
http://code.google.com/p/django-crashlog/
It will store error info in db.
DIrk
On Sun, Nov 30, 2008 at 4:36 PM, Grzegorz Szymański <[EMAIL PROTECTED]>wrote:
>
> On Sunday 30 of November 2008 09:31:55 Grzegorz Szymański wrote:
> > Hi,
> > I have no too much experience
Hi Malcolm,
> I forgot to mention this in my last reply, but you didn't actually
> answer the question that Karen asked. If you open up a Python prompt on
> your machine and do this:
>
> >>> import decimal
> >>> decimal.Decimal('1.0')
>
> does it raise an exception?
Sorry, I
On Nov 30, 1:25 am, chefsmart <[EMAIL PROTECTED]> wrote:
> Can someone throw a few ideas at me regarding this please... I'm sure
> seasoned Django-ists could have really good ideas about this...
> Thanks.
>
> On Nov 22, 10:06 pm, chefsmart <[EMAIL PROTECTED]> wrote:
>
> > Hi All,
>
> > I am
On Sunday 30 of November 2008 09:31:55 Grzegorz Szymański wrote:
> Hi,
> I have no too much experience with django and I have problem with my django
> application.
> When I switch DEBUG variable in settings.py to True the given url is
> handled correctly and page is displayed as I expect. But
Hi,
I have no too much experience with django and I have problem with my django
application.
When I switch DEBUG variable in settings.py to True the given url is handled
correctly and page is displayed as I expect. But when is switch DEBUG to
False then I get "Unhandled exception error" I
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