Re: use same database across various applications in a django project?

Why do you define this model in app1 and in app2? Define it only in app1 and import it in app2 where you need (models, views, etc) 2012/7/13 Burhan > Hi, > > Thanks for the relpy, i set db_name under as meta information, now i am > getting this error > >

Re: "Cannot convert <QueryDict:" after limiting foreign key

I think that you can replace if request.method == 'POST': form = WebrequestsForm(request.POST) with: if request.method == 'POST': form = WebrequestsForm(data=request.POST, own_id=own_id) as I said in first answer 2012/7/11 mapapage > I have a legacy db

Re: "Cannot convert <QueryDict:" after limiting foreign key

Ok, I tried your code, just added in models.py fake owners model to correct foreign key class Owners(models.Model): num = models.IntegerField() def __unicode__(self): return unicode(self.num) and create views.py with three lines of code: def page(request): form =

Re: CSRF verification failed. Request aborted.

oops) 2012/7/11 Сергей Фурсов <geyse...@gmail.com> > Some notes about your models: > 1. why do you create id field manually? Django will do it for you ;) > 2. why do you explicitly set db_table and db_column? Do you have some > legacy database? If not, django will do it for you

Re: CSRF verification failed. Request aborted.

='web_requests2', blank=True) 2012/7/11 Сергей Фурсов <geyse...@gmail.com> > Ok, I tried your code, just added in models.py fake owners model to > correct foreign key > > class Owners(models.Model): > num = models.IntegerField() > > def __unicode__(self): >

Re: CSRF verification failed. Request aborted.

= WebrequestsForm(own_id=1) return render_to_response('page.html', {'form': form}) and it works! May be problem in your views.py? 2012/7/10 Сергей Фурсов <geyse...@gmail.com> > as described in error message your view function have to use > RequestContext<http://docs.djangoproject

Re: "Cannot convert <QueryDict:" after limiting foreign key

can you provide your models.py, views.py and forms.py code relative to this problem, I'll try to help, but I need more info 2012/7/11 mapapage > I do it like this: form = WebrequestsForm(own_id=own_id, initial = {...}) >> > but I think that the prob is not there. Somehow it

Re: "Cannot convert <QueryDict:" after limiting foreign key

I can suppose that you call your modelForm's initialization like form = MyForm(request.POST, own_instance.id) but it should looks like form = MyForm(data=request.POST, own_id= own_instance.id), because there distinction between positional and keyword arguments 2012/7/11 Marilena Papageorgiou

Re: cleaned_data in forms.py?

You can try to override get_form_kwargs method def get_form_kwargs(self, step): if step == '1' cleaned_data = self.get_cleaned_data_for_step('0') or {} return {'sender': cleaned_data.get('sender', None)} else: return {} and in ContactForm2 override __init__ method

Re: cleaned_data in forms.py?

Why not use Form Wizard from django.contrib.formtools. Look at https://docs.djangoproject.com/en/dev/ref/contrib/formtools/form-wizard/#conditionally-view-skip-specific-steps Simply change show_message_form_condition method to something like def show_message_form_condition(wizard):

Re: CSRF verification failed. Request aborted.

as described in error message your view function have to use RequestContext for the template, instead of Context. your view should looks like def about(request): if request.method == 'POST':