You want to output a list of one dict per object, and you want that dict to
contain another dict inside it. So you don’t need dict2. Instead
f = file('report.json','a+')
sys.stdout = f
result = []
objects = game_objects.objects.all()
for obj in objects:
time =
On 05/04/2011 12:43 AM, Andy McKay wrote:
>
> On 2011-05-03, at 2:05 PM, Seth Gordon wrote:
>> I get an exception, complaining that Target.source does not allow
>> null values.
>
> You'll probably want to allow null values on your OneToOne field then:
>
> http:/
I have one Django model that points to another one with a OneToOneField,
sort of like this:
class Target(models.model):
# stuff
class Source(models.Model):
target = models.OneToOneField(Target)
Sometimes, given an object that is an instance of Target, I want to
navigate to its Source
On 01/05/2011 07:57 AM, James Hancock wrote:
> I think it does the same thing, but I was talking about how you cant set
> 'ordering' under the Meta class in a model.
> http://docs.djangoproject.com/en/1.2/ref/models/options/#django.db.models.Options.ordering
>
>
On 12/27/2010 09:58 AM, Henrik Genssen wrote:
> Hi,
>
> I wanted to write a test for an app, that does not have a models.py itself.
> Doing so I get:
> django.core.exceptions.ImproperlyConfigured: App with label service could not
> be found
>
> if I create a models.py with just a "pass" in it
5 matches
Mail list logo
