Tables are coming from different sources, for each single datetime value
there is a different url, in order to tie up the single source data it must
live inside its own table.
On Wednesday, March 8, 2017 at 9:11:42 AM UTC-7, Matthew Pava wrote:
>
> Why are there no better design options to
Thanks for your answer, the models represent two different tables,
identical structure but have to be segregated, there is no better design
options to implement them. Any leads on how to do the join?
>
>
>
> Models cannot be joined. There is no Model.join(). Models are objects you
> can
Greetings,
I am trying to do a join on the following 2 models (tables)
class Rio1(models.Model):
datestr = models.DateTimeField()
source = models.TextField()
dFlag = models.TextField()
url = models.TextField()
class Meta:
managed = False
db_table = 'rio1'
Greetings,
How can I access and display JSON data in a template html file? I am
getting the JSON data back in the javascript console as follows :
I tried {{ jason_data }} but no luck.
Thank you!
Here is how I am returning the json data in views.py:
return HttpResponse(json_obj,
Hello everyone,
I am trying to do the following:
Grab Year/Month values from a template page via dropdown select list and
send them via ajax post (this part is working)
Process the submitted values and return new variables to the same template
page, it works if I hard code the Month/Year but
Hello,
I can display single images that are manually uploaded fine, but how can I
display a group of images inside a certain directory? Instead of manually
typing the image file names each time there is a new image added to the
folder? So if I have 2 images or 20 images stored, I would like to
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