Thanks . It worked !!
On 26-May-2019 5:05 am, "Rob Gmail" wrote:
> Look at the new Boston.com he did a tutorial on exactly this issue
>
> Rob
> 203-671-6514
> Sent from my mobile device, please excuse the typos.
>
> On May 25, 2019, at 7:25 PM, Yoo wrote:
>
> Maybe try album__id (two underscores
Look at the new Boston.com he did a tutorial on exactly this issue
Rob
203-671-6514
Sent from my mobile device, please excuse the typos.
> On May 25, 2019, at 7:25 PM, Yoo wrote:
>
> Maybe try album__id (two underscores)? Or try album_title as defined in the
> Album model. I also advise not
Maybe try album__id (two underscores)? Or try album_title as defined in the
Album model. I also advise not to expose your primary key in the URL. If
the above did not work, check Django documentation:
https://docs.djangoproject.com/en/2.2/topics/http/urls/
On Saturday, May 25, 2019 at 2:46:58
I am currently working on a django project in which there is a music app.
The models of this app contains Albums and Songs. I want to return the http
response when the django receives a url as /music/712 , here 712 is the
object id.
Please help me out in resolving the issue.Thanks in advance.
Here
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