We are looking for django developer
Plz contact 6309620745
On Mon, Jul 5, 2021, 17:07 DJANGO DEVELOPER wrote:
> Hi there.
> I am developing a project based on adding songs to the user's library and
> to the home page.
> other users can also purchase the songs like wise people do shopping on
>
Sum thanks for your interest.
these are the screenshots of my requirements and of models.
On Mon, Jul 12, 2021 at 2:44 AM sum abiut wrote:
> I might not fully understand your question. Can you show me what you have
> done? show us your models and what you want to achieve.
>
>
>
> On Fri, Jul 9,
I might not fully understand your question. Can you show me what you have
done? show us your models and what you want to achieve.
On Fri, Jul 9, 2021 at 4:57 PM DJANGO DEVELOPER
wrote:
> sum it is giving me error of TextField is not iterable
>
> On Wed, Jul 7, 2021 at 5:30 AM DJANGO DEVELOPER
https://stackoverflow.com/questions/41689274/split-multiple-selections-into-separate-records-in-a-django-model
I also want the same result as it is mentioned here in the stackoverflow
question
On Fri, Jul 9, 2021 at 10:56 AM DJANGO DEVELOPER
wrote:
> sum it is giving me error of TextField is
sum it is giving me error of TextField is not iterable
On Wed, Jul 7, 2021 at 5:30 AM DJANGO DEVELOPER
wrote:
> so will it run smoothly?
> I mean there is no filter function there so will it filter a specific
> field and will give me count for the words?
>
> On Tue, Jul 6, 2021 at 9:40 PM sum
so will it run smoothly?
I mean there is no filter function there so will it filter a specific field
and will give me count for the words?
On Tue, Jul 6, 2021 at 9:40 PM sum abiut wrote:
> You can to something like this
>
> def count_songs(request):
> #get the field that you want to count the
You can to something like this
def count_songs(request):
#get the field that you want to count the words in it
field_name = model._meta.get_field('your_field)
word_count =Counter(field_name)
for key, value in word_count.items():
key = key
value=value
context={
'key':key,
cool :D
On Tuesday, 6 July 2021 at 10:25:06 UTC+5:30 abubak...@gmail.com wrote:
> I found this as well. and I think I want the result this way.
>
> On Tue, Jul 6, 2021 at 9:21 AM Lalit Suthar wrote:
>
>> [image: Screen Shot 2021-07-06 at 9.50.12 AM.png]
>> Counter works with words also
>>
>>
[image: Screen Shot 2021-07-06 at 9.50.12 AM.png]
Counter works with words also
nice one Simon Charette learned something new :)
On Tue, 6 Jul 2021 at 07:56, DJANGO DEVELOPER
wrote:
> thanks Simon but I am not using postgresql. I am using sqlite3 database.
> so I want a global solution, that
thanks Simon but I am not using postgresql. I am using sqlite3 database. so
I want a global solution, that work in all the databases.
On Tue, Jul 6, 2021 at 1:54 AM Simon Charette wrote:
> If you're using a PostgreSQL you might want to look at using a tsvector
> column instead which will ignore
If you're using a PostgreSQL you might want to look at using a tsvector
column instead which will ignore stop words (the, or, of, ...) and map
lexemes to their number of occurrence and position in the lyrics[0].
Assuming you were to index this column you'd be able to efficiently query
it for
Thank you Lalit bhai.
it seems to be a solution.
but what if I want to get the result for each single word rather than
single letter?
On Mon, Jul 5, 2021 at 5:43 PM Lalit Suthar
wrote:
> https://www.guru99.com/python-counter-collections-example.html
> Counter can be helpful for this situation
https://www.guru99.com/python-counter-collections-example.html
Counter can be helpful for this situation
On Mon, 5 Jul 2021 at 17:07, DJANGO DEVELOPER
wrote:
> Hi there.
> I am developing a project based on adding songs to the user's library and
> to the home page.
> other users can also
13 matches
Mail list logo
