is it actually called url.py or urls.py ?
maybe you don't have the urls file in there that you are assuming you
do.
try inserting an egregious syntax error in there just to see if its
even being loaded.
On Sep 27, 8:21 pm, Chuck Bai <[EMAIL PROTECTED]> wrote:
> In my url.py, I define the root
On Sun, 2008-09-28 at 17:54 -0700, Chuck22 wrote:
> Anyone has any clue? The problem has not been resolved yet. Any
> referrence are welcome. Thanks.
I tried to repeat the problem from the information you provided, but I
couldn't do so. Do you have a small complete example that reliably
Anyone has any clue? The problem has not been resolved yet. Any
referrence are welcome. Thanks.
chuck
On Sep 27, 2:21 pm, Chuck Bai <[EMAIL PROTECTED]> wrote:
> In my url.py, I define the root my site is like this:
> urlpatterns = patterns('',
> url(r'^$', 'views.index', name="index"),
>
i the same problem the other day... i was using the name "search" for my
named url. i dropped in the the python interpreter and tried it there,
failed. i tried some other named urls in the same urls.py, and they
worked. i didn't look at it long and just moved onto another piece of the
In my url.py, I define the root my site is like this:
urlpatterns = patterns('',
url(r'^$', 'views.index', name="index"),
...)
in my template, I have a link defined as follows:
Home
I got this error:
TemplateSyntaxError at /
Home
Caught an exception while rendering: Reverse for
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