On Aug 28, 8:53 pm, julianb <[EMAIL PROTECTED]> wrote:
> I tried several things, I think Marty's solution was among them. It
> did not throw errors, but the file I got was 0 bytes. I will try again
> and check if I made a mistake or so...
Okay, I solved the puzzle. The following works:
big =
On Aug 28, 8:44 pm, "Tim Kersten" <[EMAIL PROTECTED]> wrote:
> This should fix the error you got:
>
> import StringIO
> from django.core.files import File
> f = StringIO.StringIO()
> f.name, f.mode = 'data.xml', 'r'
> f.write(data)
> myfile = File(f)
>
Oh, I should have seen that coming. (That's the bad thing when you
write code without testing it yourself... something is often missed
:-)
This should fix the error you got:
import StringIO
from django.core.files import File
f = StringIO.StringIO()
f.name, f.mode = 'data.xml', 'r'
f.write(data)
On Aug 28, 6:03 pm, "Tim Kersten" <[EMAIL PROTECTED]> wrote:
> There's probably a better way than this though so you might want to
> wait for other replies.
>
> import StringIO
> from django.core.files import File
> f = StringIO.StringIO()
> f.write(data)
> myfile = File(f)
>
> Chart.objects.create(xml=default_storage.save('data.xml', ContentFile(data)))
ha, I was almost certain that django wouldn't make it as hard as I had
explained it. :-D Glad to see it's this easy!
Tim ^,^
--~--~-~--~~~---~--~~
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On Thu, Aug 28, 2008 at 11:44 AM, Jiri Barton <[EMAIL PROTECTED]> wrote:
> I would like Django to take care of the file naming for me. I would
> like to use a one-liner such as
>
> Chart.objects.create(xml=default_storage.save('data.xml', data))
You're nearly there for getting this to work, it's
iirc, you can use http://docs.python.org/lib/module-StringIO.html to
have a file like object from a string, and use that to make your
django File object (
http://www.djangoproject.com/documentation/files/#the-file-object ).
There's probably a better way than this though so you might want to
wait
What is the preferred way of storing generated content into file
models?
class Chart(models.Model):
xml = models.FileField(upload_to='charts')
...
I would like compute the image on the fly, using some data in the
database. How should I store the generated data? How should I use File
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