Hi guys.
I'm trying to use Rosetta ( http://code.google.com/p/django-rosetta/ )
in a view (home, a rosetta views) is using a ObjectPaginator and
InvalidPage but i've a execption
cant find module ObjectPaginator.
Googling I fix it using
from django.core.paginator import Paginator as
Yeah,
versions problems
I fix it downloading the lasted rosetta version from svn.
svn co http://django-rosetta.googlecode.com/svn/trunk/
Ty a lot
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
"Django users"
Greetings
I have a model
from django.contrib.auth.models import User
class MyUser(User):
chilean_rut = CLRutField(_('RUT'),primary_key=True)
class Meta:
admin = meta.Admin(
fields = (
(_('Personal info'), {'fields': ('first_name', 'last_name',
Greetings
I've a model
class MyUser(auth.User):
location = meta.CharField(maxlength=100, blank=True)
class META:
replaces_module = 'auth.users'
admin = meta.Admin(
list_display = ('username', 'email',
'first_name','last_name', 'lacation')
> This code looks exceptionally old, admin = meta.Admin() has been gone for
> several years, what version of django are you workign with?
>
1.1 pre-alpha
I 've in admin.py file, the main idea was show the list_display field
setted
--~--~-~--~~~---~--~~
You
At revision 9820.
???
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to django-users@googlegroups.com
To unsubscribe from this group, send email to
Yeah you're right
I can't believe that
I mix the admin settings in the class, for a short explanation.
my code:
---
models.py
from django.contrib.auth.models import User
class MyUser(User):
chilean_rut =
Thanks, I owe you a chocolate bar
I fix it
class MyUser(User):
chilean_rut = CLRutField(_('RUT'),unique=True)
some_field = models.CharField(max_length=50)
voalá
I don't really need a PK, my mistake
Thanks again.
--~--~-~--~~~---~--~~
You received this
I have a model user
class User(models.Model):
name = models.CharField(_("name"), max_length=40)
paternals = models.CharField(max_length=40)
maternals = models.CharField(max_length=40)
email = models.EmailField("e-mail")
phone = models.IntegerField(_("phone number"))
rol =
On Sat, Dec 6, 2008 at 4:59 PM, Jeff FW <[EMAIL PROTECTED]> wrote:
>
> Do you mean when a user is added via the admin interface, or when a
> user registers on the site through a view you have set up? If it's
> through a view you've made, then just add the call to send_mail() in
> the view. For
Is possible to get the html code from an administration page?
I mean, my browser is interpreting a html generated by templates and
components of my application, some banners and pictures.
Is there any way to get that code?
--~--~-~--~~~---~--~~
You received this
On Sun, Dec 7, 2008 at 2:12 AM, Karen Tracey <[EMAIL PROTECTED]> wrote:
>
>
> Something like View->Page Source from the browser menu? (That's what
> Firefox calls it -- I'd guess most browsers have some such way to see the
> raw html for a page.) Or am I misunderstanding your question?
>
> Karen
On Sun, Dec 7, 2008 at 8:45 PM, Malcolm Tredinnick <[EMAIL PROTECTED]
> wrote:
>
>
> On Sun, 2008-12-07 at 14:24 -0300, Patricio Palma wrote:
> >
> >
> > On Sun, Dec 7, 2008 at 2:12 AM, Karen Tracey <[EMAIL PROTECTED]>
> > wrote:
> >
> >
On Dec 7, 8:45 pm, Malcolm Tredinnick <malc...@pointy-stick.com>
wrote:
> On Sun, 2008-12-07 at 14:24 -0300, Patricio Palma wrote:
>
> > On Sun, Dec 7, 2008 at 2:12 AM, Karen Tracey <kmtra...@gmail.com>
> > wrote:
>
> > Something like
14 matches
Mail list logo
