Re: Simplest way to get all models for which admin interface exists

[Gelonida N]

Thanks a lot Matt,

On 03/15/2012 03:20 AM, Matt Schinckel wrote:
> All installed ModelAdmin models:
> 
 from django.contrib.admin import site
 site._registry.keys()
> 
> If you only got at this from `manage.py shell`, then you may need to
> import your urls.py file first.
> 
> Getting those that are not registered is a bit longer:
> 
 from django.db.models import get_models
 from django.conf import settings
 set(get_models()).difference(site._registry.keys())
> 
Exactly what I was looking for.


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Re: Simplest way to get all models for which admin interface exists

[Matt Schinckel]

All installed ModelAdmin models:

>>> from django.contrib.admin import site
>>> site._registry.keys()

If you only got at this from `manage.py shell`, then you may need to import 
your urls.py file first.

Getting those that are not registered is a bit longer:

>>> from django.db.models import get_models
>>> from django.conf import settings
>>> set(get_models()).difference(site._registry.keys())

Matt.

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Simplest way to get all models for which admin interface exists

[Gelonida N]

Hi,

Title says it all.

What is the simplest way to get a list of models for which an admin
interface exists?


I'd also be interested in getting a list of all models for which no
admin interface exists.

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