>The next line I quoted:
> new->physical = virt_to_phys((void *) new->memory[0]);
>...
>takes that masked physical address and applies virt_to_phys to it,
>which just seems wrong. Like I said, I don't have an i810, and I
>haven't exhaustively analyzed it to see, for instance, whether
>new->ph
On Monday 14 January 2002 9:57 am, Sottek, Matthew J wrote:
> Why do you think that isn't a virtual address? agp_alloc_page
> gets a page and returns page_addresss(page) which is the kernel
> virtual address for the page, right?
agp_alloc_page (agp_generic_alloc_page in the i810 case) indeed retu
Why do you think that isn't a virtual address? agp_alloc_page
gets a page and returns page_addresss(page) which is the kernel
virtual address for the page, right? Kernel memory is paged so
it doesn't have to be a user address to be virtual.
BTW: It works just fine. Nobody on an i810/i815 would h
