On Mon, Jan 15, 2018 at 06:27:26PM +, Eremin, Dmitry wrote:
> Hello Dan,
>
> The function kiblnd_destroy_conn() is conditionally free the conn pointer.
>
> void kiblnd_destroy_conn(kib_conn_t *conn, bool free_conn)
> {
> […]
> if (free_conn)
>LI
e.org
> Subject: RE: [lustre-devel] [bug report] staging: lustre: replace simple cases
> of LIBCFS_ALLOC with kzalloc.
>
> Hello Dan,
>
> The function kiblnd_destroy_conn() is conditionally free the conn pointer.
>
> void kiblnd_destroy_conn(kib_conn_t *conn, bool free_conn
ubject: [lustre-devel] [bug report] staging: lustre: replace simple cases of
> LIBCFS_ALLOC with kzalloc.
>
> [ This code was already buggy, it's just that Neil's change made it
>show up in static analysis. - dan ]
>
> Hello NeilBrown,
>
> The patch 3c88b
