"Patrick D. Rockwell" wrote:
> Avi Lev wrote:
>
> > this translates into: P = SIG[i=1..n](PI[j=1,j!=i..n] (dj)) -
>
> Hi. What is j! ? I know what the PI operator is, but what does
> PI[j=1,j!=1..n] do?
I would guess j = 1 to n, excluding j = i.
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