Isn't Jameson right? In the non-sequential version of RRV, if there are
only two seats to be awarded and C gets niether of them, then the sum of the
C voter's grades of the elected candidates is zero, which will contribute a
huge negative value to the sum of the logs.
But if C is given one of
: Re: [EM] electing a variable number of seats
To: fsimm...@pcc.edu
Cc: election-methods@lists.electorama.com
Isn't Jameson right? In the non-sequential version of RRV, if
there are
only two seats to be awarded and C gets niether of them, then
the sum of the
C voter's grades of the elected
fsimm...@pcc.edu wrote:
Andy,
I like the idea of iterating RRV to infinity to find the weights for a weighted voting system.
And of course,interpreted stochastically. it also gives another solution to
Jobst's consensus challenge.
I doubt that it is always the same as the Ultimate Lottery.
Yes, I do think the non-sequential version of RRV for sufficiently large
numbers of winners (with repeated wins allowed) is equivalent to the Ultimate
Lottery.The Ultimate Lottery is the lottery that maximizes the product of
ballot expectations, or equivalently the one that maximizes the sum of
2011/5/18 fsimm...@pcc.edu
Yes, I do think the non-sequential version of RRV for sufficiently large
numbers of winners (with repeated wins allowed) is equivalent to the
Ultimate Lottery.
The Ultimate Lottery is the lottery that maximizes the product of ballot
expectations, or equivalently
Jameson Quinn wrote ...
Wait a minute so under non-sequential RRV, there is no leftover Hare
quota of unrepresented voters? If 99 voters vote A100 B99 and one voter
votes C100, then C will be in the 2-member parliament? That seems broken.
FWS replies:
Your question has the same answer
] electing a variable number of seats
To: fsimm...@pcc.edu
Cc: election-methods@lists.electorama.com
Forrest,
With this profile, using RRV, Y is elected in round 1 and X is
elected in
round 2. As such, they will have equal weight.
However, we can continue to iterate RRV, without removing
Forrest,
With this profile, using RRV, Y is elected in round 1 and X is elected in
round 2. As such, they will have equal weight.
However, we can continue to iterate RRV, without removing these candidates.
The more times a candidate is chosen, the more voting weight he will get.
The election
If, in addition to allowing the number of seats to vary, you are willing to
allow different weights for different
seats, then there is another solution: find the best proportional lottery L
(e.g. by use of the Ultimate
Lottery), and then, instead of using the lottery L to choose one of the
Raph Frank wrote ...
On Fri, Feb 18, 2011 at 7:54 AM, Juho Laatu juho4880 at yahoo.co.uk wrote:
If you want to keep this property, the approach proposed by Michael Rouse
could determine
the number of board members. If most votes go to few candidates,
Charlie DeTar wrote:
Howdy,
I'm on the board of a small non-profit, and have been tasked with
revising the portion of the bylaws that defines how to elect the board
of directors. Having had some exposure to better election methods
through a colleague, I'm interested in exploring how we might
Brandon Wiley wrote:
While I think Range Voting would work great here, if for some reason it
doesn't go over (sometimes people think it seems complicated) then
Approval Voting would also be very easy to use. Again just rank
candidates by number of approvals and take the top X.
Both bloc
Another way to elect a variable number of seats is to use Monroe's method.
Here's the overview for a fixed number of winners, N. Every voter gives
every candidate a score on a numeric scale. Then we find the optimal way to
choose the N winners AND divide up the voters equally and assign them to
On Sat, Feb 19, 2011 at 5:21 AM, Kristofer Munsterhjelm
km-el...@broadpark.no wrote:
Brandon Wiley wrote:
While I think Range Voting would work great here, if for some reason it
doesn't go over (sometimes people think it seems complicated) then Approval
Voting would also be very easy to
As far as iterative methods go, I like RRV. It seems to be the natural way
to extend the divisor methods to work with range-style inputs.
But I feel like the combinatorial methods will give better proportionality
than iterative methods. If there are lots of candidates, the best
four-winner set
see the problem.
Paddy.
From: Charlie DeTar c...@media.mit.edu
To: jgilm...@globalnet.co.uk
Cc: election-methods@lists.electorama.com
Sent: Fri, 18 February, 2011 0:38:44
Subject: Re: [EM] electing a variable number of seats
On 02/17/2011 07:21 PM, James Gilmour
On Fri, Feb 18, 2011 at 7:54 AM, Juho Laatu juho4...@yahoo.co.uk wrote:
If you want to keep this property, the approach proposed by Michael Rouse
could determine
the number of board members. If most votes go to few candidates, then there
would be 5 members
(with different weight). If the
Dear Charlie,
I recommend that you should use a method to create
a proportional ranking. A proportional ranking
is a complete ranking of all candidates such that,
for every possible number M, the first M candidates
of this ranking represent the electorate in a manner
as proportional as possible.
Of Charlie DeTar
Sent: Thursday, February 17, 2011 3:39 AM
To: election-methods@lists.electorama.com
Subject: [EM] electing a variable number of seats
Howdy,
I'm on the board of a small non-profit, and have been tasked
with revising the portion of the bylaws that defines how to
elect
On 02/17/2011 07:21 PM, James Gilmour wrote:
Charlie
I see two problems here.
1. You do not give the conditions under which the constitution of this
organisation allows the number of board members to be
varied.
2. More importantly, someone needs to define the purpose of this election
Do you need to give everyone on the board identical voting power? If
not, a proxy method (where each board member's voting power is directly
related to how many votes he or she received) might work. Candidate A
might have twice the voting power of Candidate B, who might have 30
percent more
RRV is the Range Voting equivalent of STV: http://rangevoting.org/RRV.html
I implemented RRV as a Google Wave gadget back when a few people were using
that and did some test elections. In my limited experience with it I found
that RRV often gave the same results as simply ranking the candidates
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