Ahhh!  Guilty!  Thanks Ken.

>From my posting below, the part about "3dB for each shelf" is WRONG!!!!!!.   
Hopefully, I didn't corrupt any innocent minds.  It would be more correct to
say 3dB for each factor of two, 1 to 2, 2 to 4...  I'm glad that I wasn't
designing any airplanes today!  

SNIP
>>For sound, the worst case would be to add 3dB  for each shelf.  However, in
the real world, the >>noise probably won't all add together (there will be
power/phase/frequency differences).  
SNIP

Chris Maxwell | Design Engineer - Optical Division
email chris.maxw...@nettest.com | dir +1 315 266 5128 | fax +1 315 797 8024

NetTest | 6 Rhoads Drive, Utica, NY 13502 | USA
web www.nettest.com | tel +1 315 797 4449 | 




> -----Original Message-----
> From: Ken Javor [SMTP:ken.ja...@emccompliance.com]
> Sent: Wednesday, January 22, 2003 12:56 PM
> To:   Luttrell, Lyle; 'Gandler, Mark'; emc-p...@majordomo.ieee.org
> Subject:      Re: Acoustic noise calculations for multiple shelves
> 
> 
> I would further amplify on this comment.  It is not just a 10 log vs. 20 log
> calculation.  Sound power is the quantity of interest, so by definition it
> is a 10 log relationship .  But someone said add 3 dB for each added
> component.  That is incorrect.  You only add 3 dB for the second component.
> The issue is that the sound pressure level (exclusive of localized
> interference effects) adds as the square root of the sum of the squares.
> And that is what you get when you use 10 log(number of units).
> 
> 
> 


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