Using the last version 2.10.0~pre0 this problem is solved so time to
pass this discussion to the trashbin.
Should of course have checked the latest version before starting the
discussion.
Nicklas Karlsson
ons 2023-06-14 klockan 12:27 -0700 skrev John Dammeyer:
> Does your spindle have an
Of course I should have updated to latest version before posting but at
least have done this now. Update to the latest version 2.10.0~pre0
Date: Mon Jan 1 22:58:27 2024 +0100 the problem have been solved in z
direction for different coordinate systems and partly for x,y
direction.
Use G10 L2 P0
On 1/4/24 10:08, andy pugh wrote:
On Thu, 4 Jan 2024 at 13:39, gene heskett wrote:
Humm, that may call for a higher resolution spindle encoder than I have
on my Sheldon,
I have a resolver on the spindle of my lathe, which the Mesa 7i49
converts into a 14-bit number, so should have enough
On 1/4/24 10:08, andy pugh wrote:
On Thu, 4 Jan 2024 at 13:39, gene heskett wrote:
Humm, that may call for a higher resolution spindle encoder than I have
on my Sheldon,
I have a resolver on the spindle of my lathe, which the Mesa 7i49
converts into a 14-bit number, so should have enough
We had gotten some 5000 line - 2 count encoders on ebay a while back.
It certainly helped.. Higher would be nicer.,.(for bigger diameter testing)
sam
On Thu, Jan 4, 2024 at 9:08 AM andy pugh wrote:
> On Thu, 4 Jan 2024 at 13:39, gene heskett wrote:
>
> > Humm, that may call for a higher
On Thu, 4 Jan 2024 at 13:39, gene heskett wrote:
> Humm, that may call for a higher resolution spindle encoder than I have
> on my Sheldon,
I have a resolver on the spindle of my lathe, which the Mesa 7i49
converts into a 14-bit number, so should have enough resolution.
(linearity of the
On 1/3/24 18:54, andy pugh wrote:
On Wed, 3 Jan 2024 at 22:01, andy pugh wrote:
This means that the large and small arcs are tangent to each other,
which requires that their centres lie on a perpendicular line, and
that in turn means that the arc centres of small and large arcs must
be
