Re: [EVDL] charging numbers

2015-05-25 Thread Cor van de Water via EV
Rush,
The *power* is 7.2 kW and this means 7200W / 240V = 30A
The *energy* is 7.2 kW times 4 hours = 28.8 kWh

See how the units multiply just like the numbers?

7.2 x 4 = 28.8
kW  x h = kWh

You can also divide (work the other way)
so that the energy divided by the time is power:
28.8 / 4 = 7.2
kWh / h = kW

Hope this clarifies!

Cor van de Water
Chief Scientist
Proxim Wireless

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-Original Message-
From: EV [mailto:ev-boun...@lists.evdl.org] On Behalf Of Rush Dougherty via EV
Sent: Monday, May 25, 2015 1:40 PM
To: EVDL
Subject: [EVDL] charging numbers

The e-Golf has a 7.2kW charger on board and L2 charging will take 4 hrs.

So does that mean that it averages 7.5A per hour?

My logic - 7200 watts  / 4 hrs = 1800 watts per hour, 1800 watts per hour / 
240v = 7.5 A per hours. I know that I'm doing something wrong here but I just 
can't see it. Some help please.

Rush
Tucson AZ



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Re: [EVDL] charging numbers

2015-05-25 Thread Cruisin via EV
With a 24kwh battery pack it takes 4 hours for a realistic 7.5kw charger that
actually charges at 6kw to charge a pack that is about 80% depleted.



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Re: [EVDL] charging numbers

2015-05-25 Thread EVDL Administrator via EV
On 25 May 2015 at 13:40, Rush Dougherty via EV wrote:

 So does that mean that it averages 7.5A per hour?

There's no such unit as amps per hour or watts per hour.  That's like saying 
gallons per minute per hour.  It's a meaningless unit.

Amp-hours per hour and Watt-hours per hour are technically real units, but 
they're normally called amps and Watts respectively.

Think of the slash that means per in AH/h as a division sign.  The hour 
terms cancel each other out and you get just amps, because hour / hour == 1.

If the EV has a 7.2kW charger and charging takes 4 hours from 100% DOD, that 
means that (neglecting losses) the battery capacity is (4 hours * 7.2 
kilowatts) == (4 * 7.2) (kilowatts * hours) == 28.8 kilowatt hours.  

David Roden - Akron, Ohio, USA
EVDL Administrator

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