Re: physical laws as optimal inference

2009-02-14 Thread Nisheeth Srivastava
In case my original post did not make this clear, I've posted the pdf to the files section on the `everything list'. On Feb 14, 10:37 pm, John Mikes wrote: > Nisheeth? > > there are a dozen pdf Google hits in that 'half' name. Diverse titles, > topics, even several different personal names. > D

Re: physical laws as optimal inference

2009-02-14 Thread John Mikes
Nisheeth? there are a dozen pdf Google hits in that 'half' name. Diverse titles, topics, even several different personal names. Do you have a hint WHAT to (and whom to) look at? Are you at Georgia Tech? JohnM On Fri, Feb 13, 2009 at 8:44 PM, Kim Jones wrote: > > Do it Nisheeth - try and answer

Re: ASSA vs. RSSA and the no cul-de-sac conjecture was (AB continuity)

2009-02-14 Thread russell standish
On Fri, Feb 13, 2009 at 07:31:29PM +0100, Bruno Marchal wrote: > > > > I'm a little confused. Did you mean Dp here? Dp = -B-p > > > Fair question, given my sometimes poor random typo! > ... > deduce Bp) , well, if you remind the definition of the Kripke > semantics, you can see that > > Bp

Re: Qantum Immortality is not equivalent to Qantum suicide (was ASSA vs. RSSA and the no cul-de-sac conjecture)

2009-02-14 Thread Quentin Anciaux
Hi, you shouldn't equate QS with QI... QI says there always exists a next moment (hence you always stays 'conscious'). QS says that you'll always survive in one piece after putting you in front of a destruction machine and activating it... well yes by QI you'll have a next moment... but the result

Re: ASSA vs. RSSA and the no cul-de-sac conjecture

2009-02-14 Thread Jack Mallah
Hi Johnathan. I see that there are some new people like yourself here. I like to see new people and younger people take an interest in the philosophical issues, though at the same time it saddens me to see so many continue to fall victim to the the QS fallacy. I have made an important discov

Re: Born rule

2009-02-14 Thread Jack Mallah
--- On Wed, 2/11/09, Brent Meeker wrote: > >> Two copies don't increase the measure of a computation and reducing it's > >> vector in Hilbert space doesn't diminish it. > > > > If that is so then how do you explain the Born rule? > > The Born rule assumes you start with a normalized vector (i.