In a message dated 99-05-18 17:15:37 EDT, Jacques Mallah writes:
<< You don't seem to understand: that's NOT how to take an
expectation value. It bears little resemblance to the formula for an
expectation value, regardless of what "the distribution of m" is. >>
The concept of scales and
On Sat, 15 May 1999 [EMAIL PROTECTED] wrote:
> In a message dated 99-05-14 15:55:53 EDT, Jacques Mallah writes:
> Ok, now you seem to think that the expected value for the other
> box is exp((log(2m)+log(m/2))/2) given that the first box contains m and
> given a 50% chance that the second
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