Here's my response to the rest of your post. I think you're right that
with two identical deterministic computations, there is no
need to apply game theory. I think in that case you should consider
yourself to be both of them. It would not work to think there's 50% chance
you're one and 50%
On Tue, Jul 16, 2002 at 06:58:50PM -0700, Hal Finney wrote:
I am confused about the relation of S to A and B. Did S go into a
copying machine and get two copies, A and B made, in addition to S?
And now A and B are deciding what S will win?
Yes, and yes.
Why should they care? If S gets a
Wei wrote:
Here's a simplified thought experiment that illustrates the issue. Two
copies of the subject S, A and B, are asked to choose option 1 or option
2. If A chooses 1, S wins a TV (TV), otherise S wins a worse TV (TV2). If
B chooses 1, S wins a stereo, otherwise S wins TV. S prefers
On Wed, Jul 17, 2002 at 06:49:04PM -0700, Hal Finney wrote:
OK, I understand now that the utilities below are the utilities for A
and B when S gets the various items. So U(TV) is the utility for A for
S to get a TV, which is the same as the utility for B since they are
identical copies.
Wei writes:
Here's a simplified thought experiment that illustrates the issue. Two
copies of the subject S, A and B, are asked to choose option 1 or option
2. If A chooses 1, S wins a TV (TV), otherise S wins a worse TV (TV2). If
B chooses 1, S wins a stereo, otherwise S wins TV. S prefers
5 matches
Mail list logo
