RE: Problems Logging on to domain.

2001-12-31 Thread Wynkoop, John
Subject: RE: Problems Logging on to domain. This is an improper subnet for only 2 networks. Your using a class B network and 6 bits from the third octet (252). This would yield 62 subnets with 1022 hosts per subnet and a range of 4. (Check my math everyone). Why not just close off all the bits

RE: Problems Logging on to domain.

2001-12-28 Thread bmurphy
This is an improper subnet for only 2 networks. Your using a class B network and 6 bits from the third octet (252). This would yield 62 subnets with 1022 hosts per subnet and a range of 4. (Check my math everyone). Why not just close off all the bits for each subnet. Example: 172.22.64.0

RE: Problems Logging on to domain.

2001-12-28 Thread bmurphy
This is an improper subnet for only 2 networks. Your using a class B network and 6 bits from the third octet (252). This would yield 62 subnets with 1022 hosts per subnet and a range of 4. (Check my math everyone). Why not just close off all the bits for each subnet. Example: 172.22.64.0

RE: Problems Logging on to domain.

2001-12-28 Thread bmurphy
on to domain. By the wayWhat are you using to connect these two networks together? -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]] Sent: Friday, December 28, 2001 3:01 PM To: Exchange Discussions Subject: RE: Problems Logging on to domain. This is an improper

RE: Problems Logging on to domain.

2001-12-28 Thread Schwartz, Jim
Are you suffering from Multiple Personality Disorder or are you responding to your own questions? -Original Message- From: [EMAIL PROTECTED] [SMTP:[EMAIL PROTECTED]] Sent: Friday, December 28, 2001 4:19 PM To: Exchange Discussions Subject: RE: Problems Logging on to domain

RE: Problems Logging on to domain.

2001-12-28 Thread Ed Crowley
Subject: RE: Problems Logging on to domain. This is an improper subnet for only 2 networks. Your using a class B network and 6 bits from the third octet (252). This would yield 62 subnets with 1022 hosts per subnet and a range of 4. (Check my math everyone). Why not just close off all the bits