> > When I tried doing the line you defined above, I get this output: > > find: paths must precede expression > Usage: find [path...] [expression] > rm: too few arguments > Try `rm --help' for more information. > > So I did it this way: > > find /var/log -type f -mtime 5 | xargs rm > > And it works. The only thing that catches my attention is that in the > 'find' man page, '-mtime' says: > > -mtime n > File's data was last modified n*24 hours ago. > > This would seem to me to mean a static multiplyer. In other words, > '-mtime 30' would be any logs created exactly 30 days ago - not 31, not > 29. > > How would you state 'anything over 30 days'? And why did you create the > syntax the way you did above; with the '.' after 'find' and the order of > commands? > > Thanks! >
find /var/log -type f -mtime +30 will find any file in the /var/log directory that is more than 30 days old. Find expects one argument which is a path to a directory to start the search (which can be /var/log or . if your cwd is /var/log), then there are tons of possible arguments. The path must be given first, but the arguments can usually be given in any order (unless you get fancy). John
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