Re: [Factor-talk] Factor Versus Forth --- the book

2009-10-10 Thread Doug Coleman
Hi Hugh, In your book, you state that you know about the */ word in Forth, allowing you to quickly solve the resistor problem. Why not go the whole hog and ship a new word in every Forth implementation: : *+/ ( x y -- z ) 2dup + */ ; This directly solves the problem -- any competent Forth

Re: [Factor-talk] Factor Versus Forth --- the book

2009-10-10 Thread William Tanksley, Jr
Doug Coleman doug.cole...@gmail.com wrote: In your book, you state that you know about the */ word in Forth, allowing you to quickly solve the resistor problem.  Why not go the whole hog and ship a new word in every Forth implementation: : *+/ ( x y -- z ) 2dup + */ ; Doug, I see your purpose

Re: [Factor-talk] Factor Versus Forth --- the book

2009-10-10 Thread Chris Double
On Sun, Oct 11, 2009 at 11:44 AM, Hugh Aguilar hugoagui...@rosycrew.com wrote: I have an updated version. Please read it through all the way, rather than just go to the new sections, as there is a lot of rewriting throughout. Thanks for your continued help in improving this documentation. Have