Log2 is pretty fast.
We use BSR if available.
https://c9x.me/x86/html/file_module_x86_id_20.html
> On Jun 5, 2020, at 3:01 PM, Doug Coleman wrote:
>
>
> As long as you can fully round-trip the integer, it doesn't matter how many
> bytes you use.
>
> nano-count dup 4 >be be> = .
> f
>
Does it also return 8 bytes in 32-bit Windows? 06.06.2020, 01:09, "Doug Coleman" :Actually, I can be more helpful. ``nano-count`` returns a ``uint64_t`` so you need 8 bytes. In vm/os-genunix.cpp: uint64_t nano_count() { struct timespec t; int ret = clock_gettime(CLOCK_MONOTONIC, ); if (ret !=
Yes, you can see this using ripgrep:
➜ factor-master git:(master) ✗ cd vm
➜ vm git:(master) ✗ rg nano_count
os-genunix.cpp
30:uint64_t nano_count() {
os-windows.hpp <---
70:uint64_t nano_count();
os-macosx.mm
77:uint64_t nano_count() {
vm.cpp
31:
Actually, I can be more helpful. ``nano-count`` returns a ``uint64_t`` so
you need 8 bytes.
In vm/os-genunix.cpp:
uint64_t nano_count() {
struct timespec t;
int ret = clock_gettime(CLOCK_MONOTONIC, );
if (ret != 0)
fatal_error("clock_gettime failed", 0);
return (uint64_t)t.tv_sec *
Nice! I'm also using RipGrep.Thank you! 06.06.2020, 01:37, "Doug Coleman" :Yes, you can see this using ripgrep: ➜ factor-master git:(master) ✗ cd vm➜ vm git:(master) ✗ rg nano_countos-genunix.cpp30:uint64_t nano_count() {os-windows.hpp <---70:uint64_t
Hello again! My specific example is the following. I want to put the output of `nano-count` into a `byte-array`, which is fed into a hash. The current value of `nano-count` is one of the sources of randomness gathered from the system and poured into the hash. To convert the integer value into a
As long as you can fully round-trip the integer, it doesn't matter how many
bytes you use.
nano-count dup 4 >be be> = .
f
nano-count dup 8 >be be> = .
t
nano-count dup 128 >be be> = .
t
``log2 1 +`` will give you the required number of bits to store an integer.
You will want to round up to a
