The PTS value below: 000- 000- 1000 1001 1000 111-, is for a particular case. It will
vary for other videos. I hope that didn't confuse you.
On 08/28/2020 03:51 AM, Michael Koch wrote:
Hello all,
please comment if the following is right or wrong:
-- The timebase of a video (TB
On 08/28/2020 03:51 AM, Michael Koch wrote:
Hello all,
please comment if the following is right or wrong:
-- The timebase of a video (TB in setpts filter) is expressed in the unit [s]
(seconds).
-- The framerate of a video (FR in setpts filter) is expressed in the unit
[s^-1] (1/seconds).
--
Am 28.08.2020 um 13:38 schrieb Edward Park:
Hi,
Let's assume the framerate is constant. For example, I want to delay a video by
5 frames and then hstack the original video and the delayed version:
ffmpeg -i test.mp4 -vf "split[a][b];[b]setpts=PTS+5/(FR*TB)[c];[a][c]hstack" -y
out.mp4
I
Michael Koch (12020-08-28):
> Let's assume the framerate is constant. For example, I want to delay a video
> by 5 frames and then hstack the original video and the delayed version:
No, let us not make unfounded asumption and let us think in terms of
timestamps. Anything else is a waste of time.
Hi,
> Let's assume the framerate is constant. For example, I want to delay a video
> by 5 frames and then hstack the original video and the delayed version:
>
> ffmpeg -i test.mp4 -vf "split[a][b];[b]setpts=PTS+5/(FR*TB)[c];[a][c]hstack"
> -y out.mp4
I would try tpad=start=5, but I'm not
On 8/28/20, Michael Koch wrote:
> Am 28.08.2020 um 11:25 schrieb Edward Park:
>> Hello,
>>
>> I am not confident about this info but I've always thought the timebase is
>> usually the reciprocal of the framerate *or smaller*. As in, the duration
>> of a frame can be represented accurately enough
Am 28.08.2020 um 11:25 schrieb Edward Park:
Hello,
I am not confident about this info but I've always thought the timebase is usually the
reciprocal of the framerate *or smaller*. As in, the duration of a frame can be
represented accurately enough as the difference between the timestamps,
Hello,
I am not confident about this info but I've always thought the timebase is
usually the reciprocal of the framerate *or smaller*. As in, the duration of a
frame can be represented accurately enough as the difference between the
timestamps, which aren't counted using seconds, but "ticks"
Michael Koch (12020-08-28):
> -- The timebase of a video (TB in setpts filter) is expressed in the unit
> [s] (seconds).
> -- The framerate of a video (FR in setpts filter) is expressed in the unit
> [s^-1] (1/seconds).
> -- In many cases the timebase is the reciprocal of the framerate, but this
>
Hello all,
please comment if the following is right or wrong:
-- The timebase of a video (TB in setpts filter) is expressed in the
unit [s] (seconds).
-- The framerate of a video (FR in setpts filter) is expressed in the
unit [s^-1] (1/seconds).
-- In many cases the timebase is the reciprocal
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