Hello,
I would like to find a steady-state solution of an integro-differential
equation with a spacial variable in the integration limit.
So far it does not work. The minimal working example below gives wrong result.
I understand that M1 and M2 are not updated in sweeps at all. If I set up M1
Hi,
How are "mesh.cellVolumes" defined in fp.CylindricalGrid1D case?
The surface of a circle grid is not equal pi*r^2.
import fipy as fp
L= 1.; nx = 1000
mesh = fp.CylindricalGrid1D(dx=L/nx, nx=nx)
print(mesh.cellVolumes.sum())
>> 0.5
Why not pi?
How should I integrate Variables on
t;theta = 1" is not a problem, as long as it's clear from the
documentation.
--
Pavel
> On 15 Jan 2020, at 17:34, Daniel Wheeler wrote:
>
> On Wed, Jan 15, 2020 at 4:21 AM Pavel Aleynikov
> wrote:
>>
>> Hi,
>>
>> How are "mesh.cellVolumes" de
