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Mark Rotteveel
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Am 23.10.2012 13:37, schrieb Kjell Rilbe:
> But your query still seems strange... Just trying to be helpful, so I
> hope I'm not being a pain... :-)
...
> OK, but then why is R2 even
> present in the subselect?
To demonstrate an error in joins in subselects in FB3.0
> You can simplify your qu
Den 2012-10-23 13:16 skrev Frank såhär:
> On 23/10/12 11:21, Kjell Rilbe wrote:
>> Den 2012-10-23 10:32 skrev Frank såhär:
>>> select R1.RDB$RELATION_NAME
>>> from RDB$RELATION_FIELDS F1
>>> join RDB$RELATIONS R1 on F1.RDB$RELATION_NAME = R1.RDB$RELATION_NAME
>>> where F1.RDB$FIE
On 23/10/12 11:24, Dmitry Yemanov wrote:
>
> It smells like a bug caused by the new restriction ;-)
> I will investigate that, thanks.
>
thank you
Frank
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On 23/10/12 11:21, Kjell Rilbe wrote:
> Den 2012-10-23 10:32 skrev Frank såhär:
>> select R1.RDB$RELATION_NAME
>> from RDB$RELATION_FIELDS F1
>> join RDB$RELATIONS R1 on F1.RDB$RELATION_NAME = R1.RDB$RELATION_NAME
>> where F1.RDB$FIELD_NAME ='EMP_NO' and
>>(not exists(sel
23.10.2012 12:32, Frank wrote:
>
> the following statement
>
> select R1.RDB$RELATION_NAME
> from RDB$RELATION_FIELDS F1
> join RDB$RELATIONS R1 on F1.RDB$RELATION_NAME = R1.RDB$RELATION_NAME
> where F1.RDB$FIELD_NAME ='EMP_NO' and
>(not exists(select R2.RDB$RELATION_NAME
Den 2012-10-23 10:32 skrev Frank såhär:
> select R1.RDB$RELATION_NAME
> from RDB$RELATION_FIELDS F1
> join RDB$RELATIONS R1 on F1.RDB$RELATION_NAME = R1.RDB$RELATION_NAME
> where F1.RDB$FIELD_NAME ='EMP_NO' and
>(not exists(select R2.RDB$RELATION_NAME
>
Hi,
the following statement
select R1.RDB$RELATION_NAME
from RDB$RELATION_FIELDS F1
join RDB$RELATIONS R1 on F1.RDB$RELATION_NAME = R1.RDB$RELATION_NAME
where F1.RDB$FIELD_NAME ='EMP_NO' and
(not exists(select R2.RDB$RELATION_NAME
from RDB$RELATION_FIEL