Thank you once again.
Now it is much clear that sql standard have more functions and much useful.
I will wait for future improvements in Firebird. I stay longer with udfs for
now.
Regards,
Karol Bieniaszewski
On 5-12-2018 18:00, Karol Bieniaszewski liviusliv...@poczta.onet.pl
[firebird-support] wrote:
> Is this sql standard concept that i must do this in this crap way?
Yes, it is specified in SQL:2016, section 6.32 ",
"".
> SELECT substring('ab11c' similar '[[:ALPHA:]]+#"[0-9]+#"[[:ALPHA:]]+'
>
Thank you very much Mark for detailed info but i have more questions.
I am really curious.
Is this sql standard concept that i must do this in this crap way?
SELECT substring('ab11c' similar '[[:ALPHA:]]+#"[0-9]+#"[[:ALPHA:]]+' escape
'#') FROM RDB$DATABASE
Also strange that i must consume
On 3-12-2018 08:46, liviuslivius liviusliv...@poczta.onet.pl
[firebird-support] wrote:
> Firebird 3
> can someone tell me how to work with substring similar?
> SELECT substring('abc' similar 'a' escape '#') FROM RDB$DATABASE
> raise an error "Invalid SIMILAR TO pattern"
> SELECT
Hi,
Firebird 3
can someone tell me how to work with substring similar?
SELECT substring('abc' similar 'a' escape '#') FROM RDB$DATABASE
raise an error "Invalid SIMILAR TO pattern"
SELECT substring('ab11c' similar '[0-9]+' escape '#') FROM RDB$DATABASE
raise an error "Invalid SIMILAR TO
Absolutely !
It seems that the mandatory postcode field has all kinds of non-postcode
stuff in it !
For anyone else with this issue the original error was:
Invalid length parameter -2 to SUBSTRING. Negative integers are not
allowed.
Changing the query to
SELECT DISTINCT
Hello Jeremy,
Tuesday, September 6, 2016, 3:55:52 AM, you wrote:
> This simple query:
> SELECT left(c.addr_5, CHAR_LENGTH(c.addr_5)-3) as trimmed
> FROM vecusts c
>
> Produces this error
The list can't take attachments or embeds so you need to copy the
error message in text.
>
> Pressing OK I
This simple query:
SELECT left(c.addr_5, CHAR_LENGTH(c.addr_5)-3) as trimmed
FROM vecusts c
Produces this error
Pressing OK I then get correct values in the trimmed column.
Can anyone assist or tell me what I am doing wrong?
Many thanks
[Non-text
Hello
wrote:
Hello Mark,
Here the code of the sub-Procedure:
create or alter procedure P_U_CN_TO_INT (
CN_IN varchar(30))
returns (
INT_OUT integer,
STATUS smallint)
AS
declare variable I_ISNUMERIC smallint;
BEGIN
select true_param from p_u_isnumeric(:cn_in) into :i_isnumeric;
On 18-7-2014 21:03, 'checkmail' check_m...@satron.de [firebird-support]
wrote:
Hello Mark,
Here the code of the sub-Procedure:
create or alter procedure P_U_CN_TO_INT (
CN_IN varchar(30))
returns (
INT_OUT integer,
STATUS smallint)
AS
declare variable I_ISNUMERIC
Hello,
If I use the following code to extract a part of a string, it works fine:
s_datum = substring(:dat from 13 for 4);
s_datum = char(4)
Now I would give the same a stored procedure, the first input parameter is
XXX varchar(30), it returns me the integer-value and the status
On 18-7-2014 14:00, 'checkmail' check_m...@satron.de [firebird-support]
wrote:
If I use the following code to extract a part of a string, it works fine:
s_datum = substring(:dat from 13 for 4);
s_datum = char(4)
Now I would give the same a stored procedure, the first input parameter
is XXX
@yahoogroups.com
Betreff: Re: [firebird-support] substring
On 18-7-2014 14:00, 'checkmail' check_m...@satron.de [firebird-support]
wrote:
If I use the following code to extract a part of a string, it works fine:
s_datum = substring(:dat from 13 for 4); s_datum = char(4)
Now I would give the same
Hello Mark,
Here the code of the sub-Procedure:
create or alter procedure P_U_CN_TO_INT (
CN_IN varchar(30))
returns (
INT_OUT integer,
STATUS smallint)
AS
declare variable I_ISNUMERIC smallint;
BEGIN
select true_param from p_u_isnumeric(:cn_in) into :i_isnumeric;
if(i_isnumeric
Hello!
I use FirebirdClient ADO.NET http://ado.net/ Data Provider (v 3.0.2)
and try to execute query that look like this:
select * from SomeTable where substring(SomeColumn from @p0 for 4) =
'SomeString'
where @p0 - query parameter. As a result, I get an exception:
Hi ,
Could you please help me how to get the reverse substring in Firebird
like in SQL
SELECT SUBSTRING('Mahesh/pra',9,1)
Which will returns 'r' in SQL , but in firebird in is returning null
values, Please help me
Thanks,
Mahesh Pratihari
Sonata Software Limited
Phone :
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