Re: [firebird-support] order by 1, 2 - fb 32990

[acgomes2...@yahoo.com.br [firebird-support]]

hi helen... the comma is the less problem... 

 A correct sql:
 

 select N.DTEMISSAONOTA as DATA,
'DINHEIRO' as MEIO_PAGAMENTO1,
cast('DINHEIRO' as char(10)) as MEIO_PAGAMENTO2,
'00' as MEIO_PAGAMENTO,
N.VLRTOTALNOTA as VALOR,
0 as AUTENT_01,
0 as AUTENT_01_CALC,
N.AUTENTICACAO_NOTA as AUTENT_02,
3 as TIPO
 from NOTA N
 where (N.EMPRESANOTA = 1)
   and (N.DTEMISSAONOTA between '05/11/2018' and '04/11/2018')
   and (N.MODELONOTA = '55')
 order by 1, 2
 

 Error: 
 can't format message 13:587 -- message file D:\GDS_FBCLIENT\FB3\firebird.msg 
not found.
 conversion error from string "DINHEIRO".
 

 Of course, the index for the field "const" does not make much sense, the 
strange is the error.

 

 because the constant field will be the same value in all registers.

 

 Firebird: Server version: WI-V6.3.3.32900 Firebird 3.0
 


 


 

Re: [firebird-support] order by 1, 2 - fb 32990

[Helen Borrie hele...@iinet.net.au [firebird-support]]

acgomes2...@yahoo.com.br wrote:

> select

> A.Codigo

> 'DINHEIRO' FORMA_PAGTO

> FROM NF A

> where A.dataEmissao between '01.01.2018' and '31.01.2018'

>  and A.Modelo = '55'

This should work fine if you place a comma after A.Codigo.  It does
not make any sense to ORDER BY 2 (nor ORDER BY 1,2) as your literal
field FORMA_PAGTO has the same value in every row.  So:

 select
 A.Codigo,   /* << */
 'DINHEIRO' FORMA_PAGTO
 FROM NF A
 where A.dataEmissao between '01.01.2018' and '31.01.2018'
  and A.Modelo = '55'
 order by 1

HB