[Flashcoders] XML find and delete nodes

2009-06-09 Thread Merrill, Jason 
Posted this on Flash_tiger without any luck.  I know about using delete
in E4X XML to delete unwanted XML nodes, but how would you hunt down
through and delete any nodes (of a specific type, say module nodes
in the example below) that don't have any children?  

For example, if myXML happens to look like:

xml
modules
module title=apple/
module title=orange
node/
module
module title=banana
node/
module
module title=plum/  
module title=pear/
module title=pineapple
node/
module
/modules
/xml

then with that structure, I would want my code to remove the module
nodes that have the title attribute values of apple, plum, and
pear since those have no child nodes.  

I know I could figure it out through enough trial and error, but I've
spent enough time on it already.  Thought someone here could give a
quick answer. Thanks!


Jason Merrill 

Bank of  America  Global Learning 
Shared Services Solutions Development 

Monthly meetings on the Adobe Flash platform for rich media experiences
- join the Bank of America Flash Platform Community 

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Re: [Flashcoders] XML find and delete nodes

2009-06-09 Thread Rob Romanek 
This might get you pointed in the right direction. You can get an  
XMLList of all the empty nodes by this kind of statement


xml.modules.module.(children().length() == 0);

but if you then try a simple delete on that

delete xml.modules.module.(children().length() == 0);

you get:  Delete operator is not supported with operand of type XMLList.
I'm not sure right now why that wouldn't work. But you could simply  
loop through the XMLList generated and do a delete on each node


var emptyModule:XMLList = xml.modules.module.(children().length() == 0);
var index:int = emptyModule.length() - 1;
for(var i = index; i  - 1; i--){
delete emptyModule[i];
}
trace(xml);

hth,

Rob

PS so as far as the delete operator I'm not sure why  
delete(xml.modules.module) works while something like  
delete(xm.modules.module.(@title == apple)) gives an error like  
above. I would think that both those querries result in an XMLList,  
in the first case the delete occurs but not in the second... maybe  
some lunch will help my brain work better.






On 9-Jun-09, at 11:02 AM, Merrill, Jason wrote:

Posted this on Flash_tiger without any luck.  I know about using  
delete

in E4X XML to delete unwanted XML nodes, but how would you hunt down
through and delete any nodes (of a specific type, say module nodes
in the example below) that don't have any children?

For example, if myXML happens to look like:

xml
modules
module title=apple/
module title=orange
node/
module
module title=banana
node/
module
module title=plum/  
module title=pear/
module title=pineapple
node/
module
/modules
/xml

then with that structure, I would want my code to remove the module
nodes that have the title attribute values of apple, plum, and
pear since those have no child nodes.

I know I could figure it out through enough trial and error, but I've
spent enough time on it already.  Thought someone here could give a
quick answer. Thanks!


Jason Merrill

Bank of  America  Global Learning
Shared Services Solutions Development

Monthly meetings on the Adobe Flash platform for rich media  
experiences

- join the Bank of America Flash Platform Community

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Re: [Flashcoders] XML find and delete nodes

2009-06-09 Thread Steven Sacks 
Filter the XML using E4X and then make a new XML from that filtered  
result.


var xml:XML = xml
modules
module title=apple/
module title=orange
node/
/module
module title=banana
node/
/module
module title=plum/  
module title=pear/
module title=pineapple
node/
/module
/modules
/xml;
//
var list:XMLList = xml..module.(children().length() == 0);
var newXML:XML = xml/;
xml.setChildren(list);
trace(xml);
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Re: [Flashcoders] XML find and delete nodes

2009-06-09 Thread Steven Sacks 
Actually, you don't need that newXML var.  Sorry. I left that in  
during debugging.


Just setChildren the original xml, as I did.  If you want to make a  
copy without destroying the original, then setChildren() the newXML  
var instead.

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Re: [Flashcoders] XML find and delete nodes

2009-06-09 Thread Rob Romanek 
Since Jason wanted to get rid of all the nodes that were empty he  
would want to filter against !=0 and then use setChildren to refresh  
his original xml. Using setChildren is a nifty trick, much nicer than  
that delete loop I put out there.


Rob

On 9-Jun-09, at 12:24 PM, Steven Sacks wrote:

Filter the XML using E4X and then make a new XML from that filtered  
result.


var xml:XML = xml
modules
module title=apple/
module title=orange
node/
/module
module title=banana
node/
/module
module title=plum/  
module title=pear/
module title=pineapple
node/
/module
/modules
/xml;
//
var list:XMLList = xml..module.(children().length() == 0);
var newXML:XML = xml/;
xml.setChildren(list);
trace(xml);
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RE: [Flashcoders] XML find and delete nodes

2009-06-09 Thread Merrill, Jason 
Thanks Steve - have it working.  Yep, I love E4X too - still learning
all the intricacies like this, so this is another notch in my belt.

(however for anyone listening and for the archives, your code does the
opposite of what I want. It removes all nodes WITH children.  I want to
remove any nodes that DON'T have children.  Changing that one line to
look for children length greater than 0 does the trick: var list:XMLList
= xml..module.(children().length()  0); )

Thanks for your help,


Jason Merrill 

Bank of  America   Global Learning 
Shared Services Solutions Development 

Monthly meetings on the Adobe Flash platform for rich media experiences
- join the Bank of America Flash Platform Community 





-Original Message-
From: flashcoders-boun...@chattyfig.figleaf.com
[mailto:flashcoders-boun...@chattyfig.figleaf.com] On Behalf Of Steven
Sacks
Sent: Tuesday, June 09, 2009 12:25 PM
To: Flash Coders List
Subject: Re: [Flashcoders] XML find and delete nodes

Filter the XML using E4X and then make a new XML from that filtered  
result.

var xml:XML = xml
modules
module title=apple/
module title=orange
node/
/module
module title=banana
node/
/module
module title=plum/  
module title=pear/
module title=pineapple
node/
/module
/modules
/xml;
//
var list:XMLList = xml..module.(children().length() == 0);
var newXML:XML = xml/;
xml.setChildren(list);
trace(xml);
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RE: [Flashcoders] XML find and delete nodes

2009-06-09 Thread Merrill, Jason 
Rob, I came across the same problem when trying out various E4X
approaches with delete.  Steve's idea works (with the caveat his removes
populated nodes instead of unpopulated ones, but I fixed that).  

Thanks!


Jason Merrill 

Bank of  America   Global Learning 
Shared Services Solutions Development 

Monthly meetings on the Adobe Flash platform for rich media experiences
- join the Bank of America Flash Platform Community 





-Original Message-
From: flashcoders-boun...@chattyfig.figleaf.com
[mailto:flashcoders-boun...@chattyfig.figleaf.com] On Behalf Of Rob
Romanek
Sent: Tuesday, June 09, 2009 12:20 PM
To: Flash Coders List
Subject: Re: [Flashcoders] XML find and delete nodes

This might get you pointed in the right direction. You can get an  
XMLList of all the empty nodes by this kind of statement

xml.modules.module.(children().length() == 0);

but if you then try a simple delete on that

delete xml.modules.module.(children().length() == 0);

you get:  Delete operator is not supported with operand of type XMLList.
I'm not sure right now why that wouldn't work. But you could simply  
loop through the XMLList generated and do a delete on each node

var emptyModule:XMLList = xml.modules.module.(children().length() == 0);
var index:int = emptyModule.length() - 1;
for(var i = index; i  - 1; i--){
delete emptyModule[i];
}
trace(xml);

hth,

Rob

PS so as far as the delete operator I'm not sure why  
delete(xml.modules.module) works while something like  
delete(xm.modules.module.(@title == apple)) gives an error like  
above. I would think that both those querries result in an XMLList,  
in the first case the delete occurs but not in the second... maybe  
some lunch will help my brain work better.





On 9-Jun-09, at 11:02 AM, Merrill, Jason wrote:

 Posted this on Flash_tiger without any luck.  I know about using  
 delete
 in E4X XML to delete unwanted XML nodes, but how would you hunt down
 through and delete any nodes (of a specific type, say module nodes
 in the example below) that don't have any children?

 For example, if myXML happens to look like:

 xml
   modules
   module title=apple/
   module title=orange
   node/
   module
   module title=banana
   node/
   module
   module title=plum/  
   module title=pear/
   module title=pineapple
   node/
   module
   /modules
 /xml

 then with that structure, I would want my code to remove the module
 nodes that have the title attribute values of apple, plum, and
 pear since those have no child nodes.

 I know I could figure it out through enough trial and error, but I've
 spent enough time on it already.  Thought someone here could give a
 quick answer. Thanks!


 Jason Merrill

 Bank of  America  Global Learning
 Shared Services Solutions Development

 Monthly meetings on the Adobe Flash platform for rich media  
 experiences
 - join the Bank of America Flash Platform Community

 ___
 Flashcoders mailing list
 Flashcoders@chattyfig.figleaf.com
 http://chattyfig.figleaf.com/mailman/listinfo/flashcoders

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Re: [Flashcoders] XML find and delete nodes

2009-06-09 Thread Steven Sacks 
Once you really dig into E4X and realize the crazy stuff you can do,  
it's amazing.


I do some pretty crazy E4X parsing, filtering and validation with  
Gaia.  Here are some examples:


// get all nodes named page or asset in the entire XML
var nodes:XMLList = xml.descendants().(name() == page || name() ==  
asset);


// from those nodes, find any that don't have both id and src attributes
var invalidNodes:XMLList = nodes.(!attribute(id).length() || ! 
attribute(src).length());


//  get all nodes where id is not alphanumeric or begins with a number
invalidNodes = nodes.(!(/^[a-z_][a-z0-9_]*$/i.test(@id)));

// this one is complex but basically it isolates nodes that do not  
have a valid

// class package path in a package attribute
var packageNodes:XMLList = xml.descendants(). 
(attribute(package).length()  0);
invalidNodes = packageNodes.(!(/^[a-z][\w\.]*\w+$/ 
i.test(attribute(package;



As you can see, combining E4X and RegEx you can do some CRAZY stuff.
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