I see, that makes sense.
Cheers.
Jiri
Paul Andrews wrote:
Jiri wrote:
Thank you i understand it. Could u please elloborate on the last part
"..You can optimise this by using an array of pointers.."
Do you mean that this;
First calculated the range for each node.
A = 0 - 5
B = 6 - 7
C =
An easy way is to if say you have 3 objects in a list given a weight
options[0].weight = 1;
options[1].weight = 3;
options[2].weight = 4;
instead of having it have three selections, you could add the weights
and make it have 8 to choose from that point to the option.
choice[0]=0;
choice[1]=1;
Jiri wrote:
Thank you i understand it. Could u please elloborate on the last part
"..You can optimise this by using an array of pointers.."
Do you mean that this;
First calculated the range for each node.
A = 0 - 5
B = 6 - 7
C = 8 - 10
Then store in an array like so?
Array[0-5] = A
Array[6
Thank you i understand it. Could u please elloborate on the last part
"..You can optimise this by using an array of pointers.."
Do you mean that this;
First calculated the range for each node.
A = 0 - 5
B = 6 - 7
C = 8 - 10
Then store in an array like so?
Array[0-5] = A
Array[6-7] = B
Array
Jiri wrote:
Hello list,
I have an XMLList that can vary in length. I pick a random node each
time using the simple method below:
var tRandom:int = int(Math.random()*tXMLSource.nodes.length() );
return tXMLSource.nodes[tRandom]
Now i would like to change it, so that I can specify a weight t
Hello list,
I have an XMLList that can vary in length. I pick a random node each
time using the simple method below:
var tRandom:int = int(Math.random()*tXMLSource.nodes.length() );
return tXMLSource.nodes[tRandom]
Now i would like to change it, so that I can specify a weight to each
node.
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