Thanks very much Ian and Henrik. The ^ and $ was exactly what I was looking
for.
Regards,
- Michael M.
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Mendelsohn, Michael wrote:
I want the *entire* text in the text box to be considered, not just a matched
substring. Is this possible?
Use ^ to lock to the begining of the string and $ to lock to the end of
the string, use both and it will not be allowed anything other than the
expression.
Hi Michael,
Firstly, I'm not quite sure your expression is right - it says g
_or_ 1 or 2 or 3 as the first character, whereas your sample starts
with a g then a 1.
But anyway - what you need to do is to test for the beginning and
end of the string. In regular expressions, you do this with the
wow - that's really helpful - thanks a lot for your time claudius
best
a
On 4 Jul 2008, at 14:56, Claudius Ceteras wrote:
the \b boundary worked a treat - i'm just researching why it
worked now
/(\d\d\d)(?=(?:\d\d\d)*\b)/g
Find all groups of three digits < (\d\d\d) >, which are follow
>
> the \b boundary worked a treat - i'm just researching why it
> worked now
>
/(\d\d\d)(?=(?:\d\d\d)*\b)/g
Find all groups of three digits < (\d\d\d) >, which are followed by <
positive lookahead: (?= ) >
0, 3, 6, 9, ... Digits, followed by a word boundary < (?:\d\d\d)*\b >
Word boundarie
the \b boundary worked a treat - i'm just researching why it worked now
thanks for all your help guys
a
On 4 Jul 2008, at 13:17, Claudius Ceteras wrote:
To get this to also work with just the year you may replace [^\d]
with
(?:[^\d]|$) which expects a non-digit or the end of the string
O
> To get this to also work with just the year you may replace [^\d] with
> (?:[^\d]|$) which expects a non-digit or the end of the string
Or even better Replace [^\d] with \b which should also work.
regards
Claudius
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Hi,
> var sYear:String = "1234567";
> var pattern:RegExp = /(\d\d\d)(?=(?:\d\d\d)*[^\d])/g;
> sYear = sYear.replace(pattern, ",$1");
> //traces 1234567
That's because [^\d] expects a non-digit after the number
Try this:
var sYear:String = "The year when all happened was 1234567 indeed" // :
hey that's great sid - thanks
a
On 4 Jul 2008, at 12:26, Sidney de Koning wrote:
Hi Allandt,
Have you found this tool already? http://www.gskinner.com/blog/
archives/2008/03/regexr_free_onl.html
It allows you to test your regex pattern expecially for AS
And you can find a cheatsheat on Re
Hi Allandt,
Have you found this tool already?
http://www.gskinner.com/blog/archives/2008/03/regexr_free_onl.html
It allows you to test your regex pattern expecially for AS
And you can find a cheatsheat on RegEx on www.ilovejackdaniels.com and
there is ofcourse alot on whttp://www.regular-expr
hi again
i've been trying different things and it seems that the [^0] or [^\d]
is stopping it working. (I needed to use $1 rather than \1 to
reference the first group in the String.replace statement)
here is what i've got so far
var sYear:String = "1234567";
var pattern:RegExp = /(\d\d\d)(
wow - i have no idea what that means at all
time to hit the books - thanks :)
On 4 Jul 2008, at 01:09, Claudius Ceteras wrote:
Hi,
is there a way of counting back from the end of the number and
inserting the comma (even without a regular expression)? if i
use the
g modifier in the regexp (so
Hi,
> is there a way of counting back from the end of the number and
> inserting the comma (even without a regular expression)? if i
> use the
> g modifier in the regexp (so var pattern:RegExp = /000/g;), it will
> only pick up the first 000 (and every multiple thereafter)
> instead of
>
thanks a lot :)
On 2 Jul 2008, at 15:24, Juan Pablo Califano wrote:
Hi,
You can check out ascb (ActionScript Cook Book), a library with
some useful
functions. In this case, the class NumberFormat, and the method
format may
do the job.
http://www.rightactionscript.com/ascb/
Almost any f
Hi,
You can check out ascb (ActionScript Cook Book), a library with some useful
functions. In this case, the class NumberFormat, and the method format may
do the job.
http://www.rightactionscript.com/ascb/
Almost any formatNumber method you can find in many other libraries will
help you too, exc
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