wow - i have no idea what that means at all
time to hit the books - thanks :)
On 4 Jul 2008, at 01:09, Claudius Ceteras wrote:
Hi,
is there a way of counting back from the end of the number and
inserting the comma (even without a regular expression)? if i
use the
g modifier in the regexp
hi again
i've been trying different things and it seems that the [^0] or [^\d]
is stopping it working. (I needed to use $1 rather than \1 to
reference the first group in the String.replace statement)
here is what i've got so far
var sYear:String = 1234567;
var pattern:RegExp =
Hi Allandt,
Have you found this tool already?
http://www.gskinner.com/blog/archives/2008/03/regexr_free_onl.html
It allows you to test your regex pattern expecially for AS
And you can find a cheatsheat on RegEx on www.ilovejackdaniels.com and
there is ofcourse alot on
Thanks all. Rich that is my problem, you've said:
You can dispatch from one instance and listen from another
So the second instance has to be instantiated somewhere else in the
application? What if the handler for the event isn't in the same class
where I instantiate the event?
hey that's great sid - thanks
a
On 4 Jul 2008, at 12:26, Sidney de Koning wrote:
Hi Allandt,
Have you found this tool already? http://www.gskinner.com/blog/
archives/2008/03/regexr_free_onl.html
It allows you to test your regex pattern expecially for AS
And you can find a cheatsheat on
This is a dilemma that is a tough case.
I am having cross-domain loading issue. I am having an loadPolicyFile
which makes my swf to LOAD the mp3's from the other server.
-without the policyFIle it wouldnt load the mp3's at all.
but, now they are being loaded. But they are not played. no sound.
Hi,
var sYear:String = 1234567;
var pattern:RegExp = /(\d\d\d)(?=(?:\d\d\d)*[^\d])/g;
sYear = sYear.replace(pattern, ,$1);
//traces 1234567
That's because [^\d] expects a non-digit after the number
Try this:
var sYear:String = The year when all happened was 1234567 indeed // :)
To get
To get this to also work with just the year you may replace [^\d] with
(?:[^\d]|$) which expects a non-digit or the end of the string
Or even better Replace [^\d] with \b which should also work.
regards
Claudius
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Flashcoders mailing list
the \b boundary worked a treat - i'm just researching why it worked now
thanks for all your help guys
a
On 4 Jul 2008, at 13:17, Claudius Ceteras wrote:
To get this to also work with just the year you may replace [^\d]
with
(?:[^\d]|$) which expects a non-digit or the end of the string
the \b boundary worked a treat - i'm just researching why it
worked now
/(\d\d\d)(?=(?:\d\d\d)*\b)/g
Find all groups of three digits (\d\d\d) , which are followed by
positive lookahead: (?= )
0, 3, 6, 9, ... Digits, followed by a word boundary (?:\d\d\d)*\b
Word boundaries match
wow - that's really helpful - thanks a lot for your time claudius
best
a
On 4 Jul 2008, at 14:56, Claudius Ceteras wrote:
the \b boundary worked a treat - i'm just researching why it
worked now
/(\d\d\d)(?=(?:\d\d\d)*\b)/g
Find all groups of three digits (\d\d\d) , which are
Downloaded, but the code is not quite readable... I'm studying it tho.
Thanks for your help.
On Thu, Jul 3, 2008 at 4:52 AM, jonathan howe [EMAIL PROTECTED]
wrote:
I see a link into the place where they got the physics right in the
project description:
Maybe it is a cross domain issue - but also consider that there was an
error uploading to whatever domain you're using. Grab the file and make
sure it plays - one quirk with the sound player (in Flash 9 at lease),
is that it'll say its loading and playing anything. It's easily fooled
- pass
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