lf Of bjorn -
Sent: Tuesday, April 17, 2007 3:18 AM
To: flexcoders@yahoogroups.com
Subject: Re: [flexcoders] Looping through sorted ObjectProxy
Actually, it doesn't ..
If I look in my debugger - this is how the object looks:
obj.stats = Object (@3ff4c81)
[13] = Object (@3ff40c1)
[14
ferent results.
You might have to find a way to get an array.
--
*From:* flexcoders@yahoogroups.com [mailto:[EMAIL PROTECTED] *On
Behalf Of *bjorn -
*Sent:* Monday, April 16, 2007 12:06 PM
*To:* flexcoders@yahoogroups.com
*Subject:* [flexcoders] Looping through sorted Objec
Actually, it doesn't ..
If I look in my debugger - this is how the object looks:
obj.stats = Object (@3ff4c81)
[13] = Object (@3ff40c1)
[14] = Object (@40333c1)
[15] = Object (@3ec07a1)
[16] = Object (@a973301)
The code:
for( var i:String in obj.stats) {
trace(i);
}
for each (
PM
To: flexcoders@yahoogroups.com
Subject: [flexcoders] Looping through sorted ObjectProxy
I'm getting a sorted ObjectProxy from a server. In my debugger it looks like
this:
obj.stats = Object (@b90e661)
[51] = Object (@b90e541)
[52] = Object (@b90e361)
[1] = Object (@b90e121
Hey Bjørn,
"for in" loops in reverse.
"for each" should give you what you need.
regards,
Bjorn
On 17/04/2007, at 5:11 AM, bjorn - wrote:
I'm getting a sorted ObjectProxy from a server. In my debugger it
looks like this:
obj.stats = Object (@b90e661)
[51] = Object (@b90e541)
[52] = O
I'm getting a sorted ObjectProxy from a server. In my debugger it looks like
this:
obj.stats = Object (@b90e661)
[51] = Object (@b90e541)
[52] = Object (@b90e361)
[1] = Object (@b90e121)
[2] = Object (@b90e9e1)
(its week numbers linked to Objects, btw).
However, when I use for() like this:
for
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